RBSE Solutions for Class 6 Maths Chapter 4 Negative Numbers and Integers Ex 4.2

RBSE Solutions for Class 6 Maths Chapter 4 Negative Numbers and Integers Ex 4.2 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 4 Negative Numbers and Integers Exercise 4.2.

Rajasthan Board RBSE Class 6 Maths Chapter 4 Negative Numbers and Integers Ex 4.2

Question 1.
Using the number line find (RBSESolutions.com) the integer which is :
(i) 4 more than 5
(ii) + 4 more than (- 4)
(iii) 6 less than 3
(iv) + 4 less than (-1)
Solution.
Finding integer on number line
(I) 4 more than 5 i.e.,

Question 2.
Find the value of the following (RBSESolutions.com) using the number line.
(i) 9 +(- 3)
(ii) (- 4) + (- 3)
(iii) (- 2) + 5
(iv) (- 1) + 3 + (- 2)
Solution.
Operating on number line –

First move from 0 to – 1, then add 3 to – 1 and get 2 then subtracting 2 from 2 we get zero.

Question 3.
Without using (RBSESolutions.com) the number line find the sum of the following.
(i) 11 + (- 2)
(ii) (- 4) + (- 6)
(iii) (- 250) + 150
(iv) (- 380) + (- 270)
(v) (- 14) + 4
(vi) (- 180) + (- 80)
Solution.
(i) 11 + (- 2) = 11 – 2 = 9
(ii) (- 4) + (- 6) = – 4 – 6 = – 10
(iii) (- 250) + 150 = – 250 + 150 = – 100
(iv) (- 380) + (- 270) = – 380 – 270 = – 650
(v) (- 14) + 4 = – 14 + 4 = – 10
(vi) (- 180) + (- 80) = – 180 – 80 = – 260

Question 4.
Find the value of (RBSESolutions.com) the following.
(i) 137 + (- 354) +125 (ii) (- 312) + 39 + 192
(iii) 37 +(-3)+ 24 +(-8)
(iv) 102 + (- 24) + (24) + (- 11)
Solution.
(i) 137 + (- 354) + 125
= 137 – 354 + 125 = 137 + 125 – 354
= 262 – 354 = – 92
(ii) (- 312) + 39 + 192
= – 312 + 39 + 192
= – 312 + 231 = – 81
(iii) 37 + (- 3) + 24 + (- 8)
= 37 – 3 + 24 – 8 = 37+ 24 – 3 – 8
= 61 – 11 = 50
(iv) 102 + (- 24) + (24) + (- 11)
= 102 – 24 + 24 – 11
= 102 + 24 – 24 – 11
= 102 – 11 = 91

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