RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.2

RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.2 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Exercise 7.2.

Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.2

Question 1.
Subtract by the formula of eknunen (RBSESolutions.com) poorven & “Param mitra ank”.

Solution.
Subtraction with the help of eknunen poorven and “parammitraank” –

Hint :
(a) 7 cannot be subtracted from 5. Therefore, we add the (RBSESolutions.com) complementary digit of 7, the digit 3 to 5, 5 + 3 = 8, write below the sum.
(b) Put a sign of less than on the poorven digit of 5 i.e., 7, such as 7 =6.
(c) Subtract 2 from 7 (6 – 2 = 4) and write remainder 4 below.

Hint:
(a) 6 cannot be subtracted from 4. Therefore, we add (RBSESolutions.com) complementary digit of 6 i.e., 4 to 4. 4 + 4 = 8, write below the sum.
(b) Put a sign of less than on the poorven digit of 4 i.e., 8, such as 8 = 7.
(c) Subtract 5 from 8 (7 – 5 = 2) and write remainder 2 below.

Hint:
(a) 6 cannot be subtracted from Therefore, we add complementary digit of 6 i.e., 4 to 5, 5 + 4 = a, write below the sum.
(b) Put a sign of less than on the poorven digit of 5 i.e., 3, such as 3 = 2.
(c) 4 cannot be subtracted from 3=2, therefore we (RBSESolutions.com) add complementary digit of 4 i.e., 6 to 2, 2 + 6 = 8, write below the sum.
(d) Put a sign of less than on the poorven digit of 3 i.e., 4, such as 4 = 3.
(e) Subtract 1 from 4(3 – 1 = 2) and write remainder 2 below.

Hint:
(a) 3 cannot be subtracted from 0. Therefore, we add complementary digit of 3 i.e., 7 to 0, 0 + 7 = 7, write below the sum.
(b) Put a sign of less than on the poorven digit of 0 i.e., 4, such as 4 = 3.
(c) 7 cannot be subtracted from4 = 3, therefore we add (RBSESolutions.com) complementary digit of 7 i.e, 3 to 3, 3 + 3 = 6, write the sum below.
(d) Put a sign of less than on the poorven digit of 4 i.e., 8, such as 8 = 7.
(e) Subtract 5 from 8 (7 – 5 = 2) and write remainder 2 below.

Hint :
(a) 3 cannot be subtracted from 0. Therefore, we add complementary digit of 3 i.e., 7 to 0, 0 + 7 = 7, write the sum below.
(b) Put a sign of less than on the poorven digit of 0 i.e., 4, such as 4 = 3.
(c) 7 cannot be (RBSESolutions.com) subtracted from 4 = 3, therefore we add complementary digit of 7 i.e., 3 to 3, 3 + 3 = 6, write the sum below.
(d) Put a sign of less than on the poorven digit of 4 i.e., 5, such as 5 = 4 .
(e) 6 cannot be subtracted from 5 = 4, therefore we add complementary digit of 6 i.e., 4 to 4, 4 + 4 = 8, write the sum below.
(f) Put a sign of less than on the poorven digit of 5 i.e., 7, such as 7 = 6.
(g) Subtract 5 from 7 (6 – 5=1), and write remainder 1 below.

Hint :
(a) 5 cannot be subtracted from 0. therefore, we add complementary digit of 5 i.e., 5 to 0, 0 + 5 = 5, write the sum below.
(b) Put a sign of less than on the poorven digit of 0 i.e., 4, such as 4 = 3 .
(c) 8 cannot be subtracted from 4 = 3, therefore we add complementary digit of 8 i.e., 2 to 3, 3 + 2 = 5, write the sum below.
(d) Put a sign of less than on the poorven digit of 4 i.e., 4, such as 4 = 3.
(e) 5 cannot be subtracted from 4 = 3, therefore we add complementary digit of 5 i.e., 5 to 3, 3 + 5 = 8, write the sum below.
(f) Put a sign of less than on (RBSESolutions.com) the poorven digit of 4 i.e., 3, such as 3 = 2.
(g) We cannot subtract 6 from 3 = 2, therefore we add complementary digit of 6 i.e., 4 to 2, 4 + 2 = 6, write the sum below.
(h) Put a sign of less than on the poorven digit of 3 i-e., 1, such as 1 = 0.
(i) 1 = 0, write below.

Hint:
(a) 8 cannot be subtracted from 5. Therefore, we add complementary digit of 8 i.e., 2 to 5, 5 + 2 = 7, write the sun below.
(b) Put a sign of less than on the poorven digit of 5 i.e., 2, such as 2 = 1.
(c) 3 cannot be subtracted from 2 = 1, therefore we add complementary digit of 3 i.e., 7 to 1, 7 + 1 = 8, write the sum below.
(d) Put a sign of less than on the poorven digit of 2 i.e., 1, such as 1 = 0.
(e) 2 cannot be subtracted from 1 = 0, therefore we add complementary digit of 2, i.e., 8 to 0, 0 + 8 = 8, write the sum below.
(f) Put a sign of (RBSESolutions.com) less than on the poorven digit of 1 i.e., 5, such as 5 = 4.
(g) 9 cannot be subtracted from 5 = 4, therefore we add complementary digit of 9 i.e., 1 to 4, 1 + 4 = 5, write the sum below.
(h) Put a sign of less than on the poorven digit of 5 i.e., 3 such as 3 = 2.
(i) 7 cannot be subtracted from 3 = 2, therefore we add complementary digit of 7 i.e., 3 to 2, 2 + 3 = 5, write the sum below.
(j) Put a sign of less than on the poorven digit of 3 i.e., 2, such as 2 = 1.
(k) 2 = 1, write below.

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