RBSE Solutions for Class 10 Maths Chapter 1 Vedic Mathematics Ex 1.1

RBSE Solutions for Class 10 Maths Chapter 1 Vedic Mathematics Ex 1.1 is part of RBSE Solutions for Class 10 Maths. Here we have given Rajasthan Board RBSE Class 10 Maths Chapter 1 Vedic Mathematics Exercise 1.1.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 10
Subject	Maths
Chapter	Chapter 1
Chapter Name	Vedic Mathematics
Exercise	Exercise 1.1
Number of Questions Solved	20
Category	RBSE Solutions

Rajasthan Board RBSE Class 10 Maths Chapter 1 Vedic Mathematics Ex 1.1

Add by Shoonyant Method:

RBSE Class 10 Maths Chapter 1 Question 1.

Solution.

Steps:

1. 73 + 70 = 70 + 30 + 43 = 100 + 43 = 143
   Hence (RBSESolutions.com) mark an Ekadhika dot on 4 before 70.
2. Rest 42 + 54 + 89 = 89 + 11 + 43 + 43 = 100 + 86 = 186
   Hence mark on Ekadhika dot on 2 before 89.
3. Rest 86 + 75 = 86 + 41 + 61 = 100 + 6 = 161
   Hence mark on Ekadhika dot on 0 before 75.
4. Rest 61 + 01 = 62
   Hence 62 at answer’s place
5. The remaining addition process will be completed accordingly.

Vedic Maths Class 10 RBSE Pdf Question 2.

Solution.

Steps :

1. 36 + 28 = 36 + 4 + 24 = 40 + 24 = 64 + 99 = 99 + 1 + 63 = 100 + 63 = 163
   Hence, mark (RBSESolutions.com) a dot on 9 before 99.
2. Rest 63 + 21 = 84
   Hence, write 84 at answer’s place.
3. The remaining addition process will be completed accordingly.

Subtract by Vedic Method

RBSE Class 10 Maths Chapter 1 Solutions Question 3.

Solution.

Steps:
∴ 7 cannot be subtracted from 6.
So add completed digit 3 of 7 to 6 and write 9 in total along with mark an Ekadhik on previous digit 6 of 7.
Thus, complete the subtraction process.

Question 4.

Solution.

∴ 12 hr 27 m 28 sec.
Steps:

1. Measurement (RBSESolutions.com) unit in ‘time’ column-wise base is different.
2. In column of minute and second there will be two base.
   • (a) Base in unit column of both = 10
   • (b) Base in time column of both = 6
3. Base in column of hour =10
4. The base of getting complement digits in the tens columns of minute and second = 6 and in remaining base = 10
   Remark: General base considered in decimal.

Multiply

Ex 1.1 Class 10 RBSE Question 5.
31\(\frac { 1 }{ 6 }\) × 31\(\frac { 5 }{ 6 }\) (By Ekadhikena Poorvene Sutra)
Solution.

RBSE Solutions For Class 10 Maths Chapter 1 Question 6.
103 × 197 (By Ekadhikena Poorvena Sutra)
Solution.
103 × 197 = 1 × 2/03 × 97 = 2/0291 = 20291

RBSE 10th Maths Chapter 1 Question 7.
54 × 56 (By Sutra Nikilam)
Solution.
54 × 56 = 54 + 4 + 56 + 6 = 5(54 + 6)/4 × 6 = 5 × 60/24
[In R.H.S. two digits (RBSESolutions.com) and sutra is effective]
= 300/24 = 3024

Class 10 Maths Chapter 1 RBSE Question 8.
108 × 112 (By Sutra Nikhilam)
Solution.
108 × 112 = 108 + 08 × 112 + 12
= 1(108 + 12)/08 × 12 = 1 × 120/90 = 12096

Vedic Maths Class 10 RBSE Question 9.
137 × 9999 (By sutra Ekanyunena Poorvena)
Solution.
137 × 9999
L.H.S = 0137 – 1 = 0136
R.H.S. = 9999 – 0136 = 9863
137 × 9999 = 0137 – 1/9999 – 0136 = 1369863

Vedic Maths Class 10 RBSE 2020 Question 10.
46 × 99 (By sutra Ekanyunena Poorvena)
Solution.
46 × 99
L.H.S. = 46 – 1 = 45
R.H.S. = 99 – 45 = 54
46 × 99 = 46 – 1/99 – 45 = 4554

Dhwajanka Method Class 10 Question 11.
362 × 143 (By Sutra Urdhva triyak)
Solution.

RBSE Class 10 Math Chapter 1 Exercise 1.1 Question 12.
2413 × 3124 (By Sutra Urdhva Triyagbhayam)
Solution.
7 group (RBSESolutions.com) formed

Divide [Question 13 to 20]

RBSE Class 10th Math Chapter 1 Question 13.
111034 ÷ 889 (By Sutra Nikhilam)
Solution.

Divisor = 889
Revised divisor = base – divisor = 1000 – 889 = 111
Quotient = 124
Remainder = 798

RBSE Class 10 Maths Chapter 1 2020 Question 14.
3994 ÷ 97 (By Sutra Nikhilam)
Solution.

base = 100
Revised divisor = 100 – 97 = 03
Quotient = 41
Remainder = 17

Vedic Mathematics Class 10 Question 15.
2112 ÷ 97 (By Sutra Pravartya)
Solution.
This question is (RBSESolutions.com) solved by Nikhilam method not suitable for pravartya sutra.

Quotient = 21
Revised divisor = 75

Vedic Maths Class 10 Question 16.
13385 ÷ 131 (By Sutra Pravartya)
Solution.

Now, Quotient = 102
Remainder = 23

Class 10 RBSE Maths Chapter 1 Question 17.
592837 ÷ 119 (By Sutra Dhwajank)
Solution.

Vedic Mathematics Class 10 RBSE Question 18.
58764 ÷ 59 (By Sutra Dhwajank)
Solution.

1. Divisor = 59, Mukhyank = 5, Dhwajank = 9
2. In third column one digit of divident = 4
3. 58 ÷ 5 = 11, Quotient = 11, Remainder = 3.
4. Corrected dividend = 37 – 11 ÷ 9 = 37 – 99
   Since corrected (RBSESolutions.com) dividend is negative so the second digit of quotient must be 9 instead of 11.
   That is why the terms (ii) and (iv) are rejectable.
5. Again 58 ÷ 5, Quotient first digit = 9, Remainder = 13
6. New dividend = 137,
   Corrected dividend = 137 – 9 × 9 = 56
7. 56 ÷ 5, Quotient second digit = 9, Remainder = 11
8. New dividend = 116,
   Correctly divisor = 116 – 9 × 9 = 35
9. 35 ÷ 5, Quotient second digit = 6, Remainder = 5
10. New divisor = 54
    Corrected divisor and final remainder = 54 – 6 × 9 = 54 – 54 = 0.
    Thus quotient = 996, Remainder = 0.

Chapter 1 Class 10 Maths RBSE Question 19.
92358 ÷ 151 (by dhwajank sutra)
Solution.

Hint :

1. Divisor = 151, Mukhyank 15, Dhwajank = 1
2. In third (RBSESolutions.com) column one digit of dividend = 8
3. 92 ÷ 15, Quoient first digit = 6, Remainder = 2
4. New dividend = 23, corrected dividend = 23 – 6 x 1 = 17
5. 17 ÷ 15, Quotient second digit = 1, Remainder = 2
6. New dividend 25, correctly dividend = 25 – 1 × 1 =24
7. 24 ÷ 15, quotient third digit = 1, Remainder = 9
8. New dividend = 98.
   Corrected dividend are final remainder = 98 – 1 × 1 = 97
   Quotient = 611, Remainder = 97

RBSE Class 10th Maths Chapter 1 Question 20.
12345 ÷ 91 (By Sutra Dhwanjank)
Solution.

Hint:

1. Divisor = 91, Mukhaynak = 9, dhwajank = 1
2. In third part divided one digit = 5
3. 12 ÷ 9 = Quotient first digit = 1, Remainder = 3
4. New dividend = 33, (RBSESolutions.com) Corrected dividend = 33 – 1 × 1 = 32
5. 32 ÷ 9 quotient second digit = 3, Remainder = 5
6. New dividend = 54, corrected dividend = 54 – 3 × 1 = 51
7. 51 ÷ 9 quotient third digit = 5, Remainder = 6
8. New dividend = 65,
   Corrected dividend or final remainder = 65 – 5 × 1 = 60
   Quotient = 135, Remainder = 60

We hope the given RBSE Solutions for Class 10 Maths Chapter 1 Vedic Mathematics Ex 1.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 10 Maths Chapter 1 Vedic Mathematics Exercise 1.1, drop a comment below and we will get back to you at the earliest.