RBSE Solutions for Class 10 Maths Chapter 1 Vedic Mathematics Ex 1.2

RBSE Solutions for Class 10 Maths Chapter 1 Vedic Mathematics Ex 1.2 is part of RBSE Solutions for Class 10 Maths. Here we have given Rajasthan Board RBSE Class 10 Maths Chapter 1 Vedic Mathematics Exercise 1.2.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 10
Subject	Maths
Chapter	Chapter 1
Chapter Name	Vedic Mathematics
Exercise	Exercise 1.2
Number of Questions Solved	32
Category	RBSE Solutions

Rajasthan Board RBSE Class 10 Maths Chapter 1 Vedic Mathematics Ex 1.2

By the method of upsutra yavaduham Tavaduram find the square:

RBSE Class 10 Maths Chapter 1 Solutions Question 1.
93
Solution
93² = 9(93 + 3)/(3)²
= 9(96)/9 Base = 10
= 864/9 Sub-base = 10 × 9
8649 (RBSESolutions.com) deviations = + 3

RBSE Solutions For Class 10 Maths Chapter 1 Question 2.
206
Solution
206² = 2(206 + 06)/(06)²
= 2(212)/36   Base = 100
= 424/36   Sub-base = 100 × 2
= 42436   deviation = +06

Ex 1.2 Class 10 RBSE Question 3.
211
Solution
211² =2(211 + 11)/(11)²
= 2(222)₁21 Base = 100
= 444/₁21 Sub-base = 100 x 2
= 44521 (RBSESolutions.com) deviation = +11

RBSE Class 10 Maths Chapter 1 Question 4.
405
Solution
405² = 4(405 + 05)/(05)²
= 4(410) / 25 Base = 100
= 1640 / 25 Sub-base = 100 × 4
= 164025 deviation = +05

Vedic Mathematics Class 10 Question 5.
16
Solution

RBSE Class 10 Maths Chapter 1 2021 Question 6.
31
Solution

Vedic Mathematics Class 10 RBSE Question 7.
24
Solution

Vedic Maths Class 10 RBSE 2021 Question 8.
56
Solution

By Sutra Ekadhikena Poorvena find the square of the following:

Vedic Maths Class 10 RBSE Pdf Question 9.
45
Solution
45² = 4 × 5 / 5 × 5 = 20 / 25 = 2025

Exercise 1.2 Class 10 Maths Question 10.
85
Solution
85² = 8 × 9 / 5 × 5 = 72 / 25 = 7225

Vedic Maths Class 10 Question 11.
115
Solution
115² = 11 × 12 / 5 × 5 = 132 / 25 = 13225

Vedic Maths Chapter 1 Question 12.
125
Solution
125² = 12 × 13 / 5 × 5 = 156 / 25 = 15625

By Sutra Sankaiana – Viyavkalan find the square of the following:

RBSE 10th Maths Chapter 1 Question 13.
23
Solution
23² = (23 + 3)(23 – 3) + 3²
= 26 × 20 + 3²
= 520 + 9
= 529

RBSE Maths Solution Class 10 Chapter 1 Question 14.
38
Solution
38² = (38 + 8)(38 – 8) + (8)²
= (46 × 30) + 64
= 1380 + 64
= 1444

Class 10 Maths Chapter 1 Exercise 1.2 Question 15.
69
Solution
69² = (69 + 9)(69 – 9) + 9²
= (78)(60) + 81
= 4680 + 81
= 4761

Vedic Maths Class 10 RBSE English Medium Question 16.
89
Solution
89² = (89 + 9)(89 – 9) + 9²
= (98)(80) + 81
= 7840 + 81
= 7921

By Dwandwa Yog find the Square:

Exercise 1.2 Class 10 Maths Solution Question 17.
362
Solution
Writting five digit groups of (RBSESolutions.com) then number 362 – 3, 36, 362, 62 and 2 and the dwandwa yog of these five digit groups

Chapter 1 Class 10 Maths RBSE Question 18.
453
Solution
Five digit groups of (RBSESolutions.com) the no. 453 – 4, 45, 453, 53 and 3 Dwandwa yog of these groups

Ex 1.2 Class 10 Maths Question 19.
4312
Solution
Seven digit group of the (RBSESolutions.com) number 4312 – 4, 43, 431, 4312, 321, 12 and 2 Dwandwa yog of these groups

Exercise 1.2 Class 10 Question 20.
2456
Solution
Seven digit group of the (RBSESolutions.com) number 2456 – 2, 24, 2456, 456 and 6 Dwandwa yog of these groups

Find cube by Sutra Nikhilam

Maths Class 10 Chapter 1 Exercise 1.2 Question 21.
14
Solution
We know (RBSESolutions.com) that

Vedic Maths Class 10 RBSE Question 22.
97
Solution
We know (RBSESolutions.com) that

1.2maths Class 10 Question 23.
27
Solution
base = 10, sub-base = 10 × 2, sub-base digit = 2, deviation = +7
We know (RBSESolutions.com) that

Class 10 Maths 1.2 Question 24.
395
Solution
Here base = 100, sub-base digit = 4, deviation = – 05,
We know (RBSESolutions.com) that

By Upsutra Anurupyena find the cube of the following:

10 Class Math Exercise 1.2 Solution Question 25.
16³
Solution

Math 1.2 Class 10 Question 26.
33³
Solution

Class 10 Maths Ex 1.2 Question 27.
41³
Solution

1.2 Class 10 Question 28.
52³
Solution

Find cube by sutra Ekadhikene purvena
Formula: Square of ten’s digit × It’s more (RBSESolutions.com) than one/square of ten’s place digit × deviation/3 × ten’s digit × (unit digit)²/(unit digit)³.
where deviation = unit digit × 3 – 10

Class 10 Maths Chapter 1 All Formulas Question 29.
45
Solution

Exercise 1.2 Question 30.
73
Solution

Maths RBSE Solutions Class 10 Question 31.
24
Solution

RBSE Class 10 Chapter 1 Question 32.
106
Solution

Steps: Deviation = 6 × 3 ~ 10 = 8

We hope the given RBSE Solutions for Class 10 Maths Chapter 1 Vedic Mathematics Ex 1.2 will help you. If you have any query regarding Rajasthan Board RBSE Class 10 Maths Chapter 1 Vedic Mathematics Exercise 1.2, drop a comment below and we will get back to you at the earliest.