# RBSE Solutions for Class 12 Maths Chapter 10 Definite Integral Ex 10.2

## Rajasthan Board RBSE Class 12 Maths Chapter 10 Definite Integral Ex 10.2

Find the value of the following integrals :

RBSE Solutions For Class 12 Maths Chapter 10.2 Question 1. Solution: Ex 10.2 Class 12 RBSE Question 2. Solution: RBSE Solutions For Class 12 Maths Chapter 10 Question 3. Solution:  RBSE Solutions For Class 12 Maths Chapter 10 Miscellaneous Question 4. Solution: 12 Maths RBSE Solution Question 5. Solution:  RBSE Solution 12 Math Question 6. Solution:  RBSE Solutions Class 12 Maths Ex 10.2 Question 7. Solution: Class 12 Math Ex 10.2 Question 8. Solution: Maths RBSE Solutions Class 12 Question 9. Solution: Similar Question Solution: 12th RBSE Solutions Question 10. Solution:  Class 12 Hindi RBSE Solutions Question 11. Solution:  RBSE Solution 12th Class Question 12. Solution: RBSE Solutions Of Class 12 Question 13. Solution:  12th Class RBSE Solution Question 14. Solution: RBSE Solutions For Class 12 Maths Chapter 10.2 Question 15. Solution: 12th RBSE Solution Question 16. Solution:  RBSE Solution For Class 12th Question 17. Solution: RBSE Solution Class 12th Maths Question 18. Solution:  RBSE Solution Class 12 Hindi Question 19. Solution: RBSE Solution Of Class 12th Question 20. Solution:  12th Maths RBSE Solution Question 21. Solution: 12 Class RBSE Solution Question 22. Solution:  RBSE Solutions 12th Hindi Question 23. Solution:  RBSE Solution 12th Question 24. Solution: RBSE Solutions 12 Question 25. Solution: RBSE Solutions 12 Maths Question 26. Solution: $$[\log (x+1)]_{1}^{2}-[\log (x+2)]_{1}^{2}$$
= [log (2 + 1) – log (1 + 1)]
– [log (2+ 2)-log (1 +2)]
= log 3 – log 2 – log 4 + log 3
= 2 log 3 – (log 2 + log 4)
= 2 log 3 – log 8
= log $$\frac { { 3 }^{ 2 } }{ 8 }$$ = log $$\frac { 9 }{ 8 }$$