RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3

Rajasthan Board RBSE Class 12 Maths Chapter 13 Vector Ex 13.3

RBSE Solutions For Class 12 Maths Chapter 13.3 Question 1.
Find vector product of vectors
RBSE Solutions For Class 12 Maths Chapter 13.3
and
RBSE Solutions For Class 12 Maths Chapter 13
Solution:
Exercise 13.3 Class 12 RBSE Solution
Ex 13.3 Class 12 RBSE Solution
RBSE Solutions For Class 12 Maths Chapter 13 Question 2.
Find perpendicular unit vector of vectors
RBSE Class 12 Maths Chapter 13
and
Maths Class 12 Exercise 13.3 RBSE Solution
Solution:
Exercise 13.3class 12 RBSE Solution
Class 9 Math Exercise 13.3 RBSE Solution
Exercise 13.3 Class 12 RBSE Question 3.
For vectors \(\overrightarrow { a } \) and \(\overrightarrow { b } \), prove that
Ex 13.3 Class 12 RBSE Solution
Solution:
12th RBSE Maths Solution Ex 13.3
Ex 13.3 Class 12 RBSE Question 4.
Prove that
RBSE Solutions For Class 9 Maths Chapter 13
Solution:
According to question,
RBSE 12 Maths Solution Ex 13.3
RBSE Class 12 Maths Chapter 13 Question 5.
If \(\overrightarrow { a } \), \(\overrightarrow { b } \), \(\overrightarrow { c } \) are unit vectors, such that
\(\overrightarrow { a } \) . \(\overrightarrow { b } \) = 0 = \(\overrightarrow { a } \) . \(\overrightarrow { c } \) and angle between \(\overrightarrow { b } \) and \(\overrightarrow { c } \) is \(\frac { \pi }{ 6 } \), then prove that \(\overrightarrow { a } \) = ± 2 (\(\overrightarrow { b } \) × \(\overrightarrow { c } \))
Solution:
Given that
Ex 13.3 Solutions Class 12 RBSE Solution
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
Maths Class 12 Exercise 13.3 Question 6.
Find the value of
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
Solution:
We know that if \(\overrightarrow { a } \) and \(\overrightarrow { b } \) are two vectors and θ is the angle between them, then
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
Exercise 13.3class 12 Question 7.
Find vector perpendicular to the vectors
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
and
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
whose magnitude is 9 unit.
Solution:
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
Class 9 Math Exercise 13.3 Question 8.
Show that:
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
also, explain geometrically.
Solution:
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
= 2(vector area of parallelogram ABCD).
Thus we conclude that area of parallelogram whose adjacent sides are diagonals of given parallelogram is twice the area of given parallellogram.

Ex 13.3 Class 12 Question 9.
For any vector \(\overrightarrow { a } \), prove that
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
Solution:
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3

Ex 13.3 Class 10 Question 10.
If two adjacent sides of a triangle are represented by vectors
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
and
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3
then find the area of triangle.
Solution:
RBSE Solutions for Class 12 Maths Chapter 13 Vector Ex 13.3

RBSE Solutions for Class 12 Maths

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