# RBSE Solutions for Class 6 Maths Chapter 13 Ratio and Proportion Additional Questions

RBSE Solutions for Class 6 Maths Chapter 13 Ratio and Proportion Additional Questions is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 13 Ratio and Proportion Additional Questions.

 Board RBSE Textbook SIERT, Rajasthan Class Class 6 Subject Maths Chapter Chapter 13 Chapter Name Ratio and Proportion Exercise Additional Questions Number of Questions 17 Category RBSE Solutions

## Rajasthan Board RBSE Class 6 Maths Chapter 13 Ratio and Proportion Additional Questions

Multiple Choice Questions

Question 1.
Fraction from of (RBSESolutions.com) ratio 9 : 19 is
(i) $$\frac { 1 }{ 9 }$$
(ii) $$\frac { 1 }{ 12 }$$
(ii) $$\frac { 9 }{ 19 }$$
(iv) $$\frac { 19 }{ 2 }$$

Question 2.
Rs. 400 can be divided in Ram and Rahim of ratio 3 : 5, Then money of Ram will be
(i) Rs. 50
(ii) Rs. 80
(iii) Rs. 150
(iv) Rs. 250

Question 3.
Simplest form of (RBSESolutions.com) Ratio 2 m 20 cm : 11 cm, is
(i) 20 :1
(ii) 1 : 20
(ii) 220 : 11
(iv) 11 : 220

Question 4.
Value of x in, 2 : 3 :: 10 : x is
(i) 20
(ii) 60
(iii) 15
(iv) 30

Question 5.
$$\frac { \Box }{ 12 } =\frac { 8 }{ 10 }$$ are in (RBSESolutions.com) proportion then what will be in box
() 9
(ii) 9.6
(iii) 10
(iv) 10.6

Question 6.
Equivalent ratio of 2 : 3 is
(i) 8 : 6
(ii) 5 : 12
(iii) 6 : 9
(iv) 16 : 12

Answers:
1. (iii)
2. (iii)
3. (i)
4. (iii)
5. (ii)
6. (iii)

Question 1.
Fill in the blanks :
(i) For comparison by (RBSESolutions.com) ratio, the two quantities …………… must be in some
(ii) Ratio can be represented by …………… sign.
(iii) Proportion can be represented by …………… sign.
(iv) A relation, which says in same type of quantities, how many times one quantity is to the other quantity, is called ……………
Answer:
(i) unit
(ii) :
(iii) ::
(iv) ratio

Very Short Answer Type Questions

Question 1.
Express the following (RBSESolutions.com) ratios in simplest form
(i) 15 : 20
(ii) 28 : 35
Solution:
(i) 15 : 20 = $$\frac { 15 }{ 20 }$$ = $$\frac { 3 }{ 4 }$$ = 3 : 4
(ii) 28 : 35 = $$\frac { 28 }{ 35 }$$ = $$\frac { 4 }{ 5 }$$ = 4 : 5

Question 2.
Which is greater ratio in 2 : 3 and 3 : 5
Solution:
Fraction from of ratios = $$\frac { 2 }{ 3 }$$ and $$\frac { 3 }{ 5 }$$
Fractions with like denominator = $$\frac { 10 }{ 15 }$$ and $$\frac { 9 }{ 15 }$$
Thus, greater ratio will be $$\frac { 10 }{ 15 }$$, i.e. 2 : 3

Question 3.
Are quantities 19, 16, 21, and 24 in (RBSESolutions.com) proportion or not?
Solution:
According to question
Product of extreme terms = 19 × 24 = 456 …………… (i)
Product of middle terms= 16 × 21 = 336 …………… (ii)
Both (i) and (ii) are not equal.
19, 16, 21 and 24 are not in proportion.

Question 4.
$$\frac { 20 }{ 5 } =\frac { \Box }{ 6 } =\frac { 12 }{ 3 }$$ find the (RBSESolutions.com) number, which fill the box.
Solution:

Question 5.
Divide 20 pend (RBSESolutions.com) in Sheela and sangeeta in ratio 3 : 2.
Solution:
Sum of ratios of both quantities = 3 + 2 = 5
Total number of pen. = 20
∴ Sheela got pen = $$\frac { 3 }{ 5 }$$ × 20 = 3 × 4 = 12
and Sangeeta got pen = $$\frac { 2 }{ 5 }$$ × 20 = 2 × 4 = 8.

Short Answer Type Questions

Question 1.
If cost of 6 cane of Juice is Rs. 210. then find the (RBSESolutions.com) cost of 4 cane of Juice?
Solution:
Cost of 6 cones of Juice = Rs. 210
∴ Cost of 1 cone of Juice = $$\frac { 210 }{ 6 }$$ = Rs. 35
∴ Cost of 4 cone of Juice = 35 × 4 = Rs. 140
The cost of 4 cone of Juice is Rs. 140.

Question 2.
Aneesh made 42 runs in 6 overy and Anup made 63 runs in 7 overs. Who (RBSESolutions.com) made more runs per over?
Solution:
∵ Aneesh made runs in 6 overs = 42
∴ Aneesh made runs in 1 overs = $$\frac { 42 }{ 6 }$$ = 7
∵ Anup made runs in 7 overs = 63
∴ Anup made runs in 1 overs = $$\frac { 63 }{ 7 }$$ = 9
∴ Anup made more runs per over.

Question 3.
Find the ratio of (RBSESolutions.com) each of the following
(a) 30 minute to 1.5 hours
(b) 40 cm 1.5 m.
Solution:
(a) 30 min to 1.5 hours ( ∵ 1 hours = 60 min )
= 30 min : 1.5 × 60 min
= 30 min : 90 min
= 30 : 90
= 1 : 3 [Divide first and second quantity by their H.C.F. = 30]

(b) 40 cm to 1.5 m, ( ∵ 1 m = 100 cm )
= 40 cm : 1.5 × 100 cm
= 40 cm : 150 cm
= 40 : 150
= 4 : 15 [Divide first and second quantities by their H.C.F = 10]

Question 4.
Are ratios 15 cm to 2 m and 10 sec to 3 min, in (RBSESolutions.com) proportion?
Solution:
⇒ By ratio of 15 cm to 2 m.
= 15 : 2 × 100 = 15 : 200 (∵ 1 m = 100 cm)
⇒ by ratio of 10 sec to 3 min.
= 10 sec : 3 × 60 sec ( ∵ 1 min = 60 sec )
= 10 : 180 = 1 : 8
$$\frac { 3 }{ 40 } \neq \frac { 1 }{ 18 }$$
Thus, they are not in proportion

Question 5.
Are following (RBSESolutions.com) quantities in proportion
(a) 15, 45, 40, 120
(b) 33, 121, 9, 96
Solution:
(a) 15 : 45 and 40 : 120
Product of extreme terms = 15 × 120 = 1800
Product of middle terms = 45 × 40 = 1800
∴ Product of extreme terms = Product of middle terms
∴ 15, 45, 40, and 120 are in proportion.

(b) 33 : 121 and 9 : 96
Product of (RBSESolutions.com) extreme terms = 33 × 96 = 3168
Product of middle terms = 121 × 9 = 1089
∴ Product of extreme terms ≠ Product of middle terms
∴ 33, 121, 9, and 96 are not in proportion.

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