RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7

RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Exercise 7.7.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 6
Subject Maths
Chapter Chapter 7
Chapter Name Vedic Mathematics
Exercise Ex 7.7
Number of Questions 1
Category RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7

Question 1.
Multiply (Using formula of Nikhilam).
(i) 12 × 13
(ii) 11 × 19
(iii) 13 × 15
(iv) 8 × 7
(v) 6 × 9
(vi) 8 × 12
(vii) 102 × 104
(viii) 106 × 107
(ix) 112 × 109
(x) 91 × 98
(xi) 96 × 94
(xii) 98 × 104
(xiii) 85 × 93
Solution.
On multiply by (RBSESolutions.com) formula of Nikhilam :
(i) 12 × 13
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 1
Hints :
(a) Multiple number 12 = 10 + 2 which is 2 more than 10 and 13 = 10 + 3, which is 3 more than 10. We write + 2, + 3 as in form of deviation.
(b) Write the numbers up and down and deviation (RBSESolutions.com) in front of them.
(c) Product of deviation (+ 2 × + 3) = 6, would be written on the right side of slanted line.
(d) Write 12 + 3 or 13 + 2 = 15 on left side.
(e) Product is 156 after removing the diagonal line.

RBSE Solutions

(ii) 11 × 19
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 2
Hints :
(a) Multiple number 11 = 10 + 1, which is 1 more than 10, and 19 = 10 + 9, which is 9 more than 10, we write it as + 1, + 9 as in form of deviation.
(b) Write the (RBSESolutions.com) number up and down and deviation in front of them.
(c) Product of deviation (+ 1) × (+ 9) = 9, would be written on the right side of slanted line.
(d) Write 11 + 9 or 19 + 1 = 20 on left side.
(e) Product is 209 after removing the diagonal lines.

(iii) 13 × 15
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 3
Hints :
(a) Multiple 13 = 10 + 3, which (RBSESolutions.com) is 3 more than 10, and 15-10 + 5 which is 5 more than 10, we write + 3 and + 5 as in form of deviation.
(b) Write the numbers up and down and deviation in front of them.
(c) Product of deviations (+ 3) × (+ 5) = 15 is written on the right side of the diagonal lines.
(d) Write in the left side (13 + 5) or (15 + 3) = 18.
(e) There will be only one number on the right hand side because in base 10, there is one zero.
(f) In the product of deviation (15) unit digit 5 on R.H.S. and add 1 on the left side. (In form of base 10)
(g) On L.H.S. 18 + 1 = 19.
(h) On removing slanted line product is 195.

(iv) 8 × 7
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 4
Hints :
(a) Multiple 8 = 10 – 2, which is 2 less than 10 and 7 = 10 – 7, which (RBSESolutions.com) is 3 less than 10, we write – 2, – 3 as in form of deviation.
(b) Write the numbers up and down and deviation in front of them.
(c) Product of deviation (- 2 × – 3) = 6, would be written on the right side of the slanted line.
(d) Write in the left side (8 – 3) or (7 – 2) = 5.
(e) On removing slanted line product is 56.

(v) 6 × 9
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 5
Hints :
(a) Multiple 6 = 10 – 4 which is 4 less than 10 and 9 = 10 – 1 which is 1 less than 10. We write – 4 and – 1 as in the form of deviation.
(b) Write the numbers up and down and (RBSESolutions.com) deviation in front of them.
(c) Product of deviation (- 4) × (-1) = 4, would be written on the right side of the slanted line.
(d) Write in the left side (6 – 1) or ( 9 – 4) = 5.
(e) On removing slanted line product is 54.

RBSE Solutions

(vi) 8 × 12
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 6
Hints :
(a) Multiple 8 = 10 – 2, which (RBSESolutions.com) is 2 less than 10, and 12 = 10 + 2, which is 2 more than 10. We write – 2 and + 2 as in form of deviation.
(b) Write numbers up and down and deviation in front of them.
(c) Product of deviation (- 2) × (+ 2) = 4, would be written on the right of the slanted line.
(d) Write in the left side (8 + 2) or (12 – 2) = 10.
(e) The product of deviation is negative on the right hand side, for converting it into positive take 1 from left side as 1 × 10 = 10 towards right hand side.
(f) There would be 10 – 1 = 9 on the left hand side.
(g) On right hand side 10 – 4 = 6.
(h) On removing slanted line, product is 96.

RBSE Solutions

(vii) 102 × 104
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 7
Hints :
(a) Multiple 102 = 100 + 02 , which is 2 more than 100 and 104 = 100 + 4 which is 4 more than 100, we write + 2 and + 4 as in form of deviation.
(b) Write the numbers up and down and deviation in front of them.
(c) Product of deviation (+ 02) × (+ 04) = 08, would be written on the right of the slanted line.
(d) Write in (RBSESolutions.com) the left side (102 + 04) or (104 + 02) = 106.
(e) Multiplication of deviation is + 8 on the right hand side (two zeroes in 100). Therefore, there must be 2 digits on right side. So, write 08 instead of + 8.
(f) On removing slanted line, product is 10608.

(viii) 106 × 107
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 8
Hints :
(a) Multiple 106 = 100 + 06, which is 6 more than 100 and 107 = 100 + 7 which is 7 more than 100, we write + 06 and + 07 as in form of deviation.
(b) Write the numbers up and down and their deviation in front of them.
(c) Product of deviation + 06 × + 07 = + 42, would be written on the right side of the diagonal line.
(d) Write on the left side (106 + 07) or (107 + 06) = 113.
(e) Product of multiplication of (RBSESolutions.com) deviation on the right hand side is + 42 and there are two zeroes in base number 100. Therefore, two digits on the right hand side.
(f) On removing slanted line, product is 11342.

(ix) 112 × 109
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 9
Hints :
(a) Multiple 112 = 100 + 12, which is 12 more than 100 and 109 = 100 + 9 which is 9 more than 100, we write 12 and + 09 as in form of deviation.
(b) Write the numbers up and down and their deviation in front of them.
(c) Product of deviation (+ 12 × + 09) = + 108 would be written on the right side of the diagonal line.
(d) Write on the left side (112 + 09) or (109 +12) = 121.
(e) On the right side (RBSESolutions.com) multiplication of deviation is 108 (two zeroes in base 100) therefore their will be two digits in right side i.e., 08. Add 1 to the left side.
(f) On left side 121 + 1 = 122.
(g) On removing slanted line, product is 12208.

(x) 91 × 98
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 10
Hints :
(a) Multiple 91 = 100 – 09 which is 9 less than 100 and 98 = 100 – 2, which is 2 less than 100, we write – 09 and — 02 as in form of deviation.
(b) Write the numbers up and down and their deviation in front of them.
(c) Product of deviation – 09 × – 02 = + 18, would be written on the right side of the diagonal line.
(d) Write (RBSESolutions.com) on the left side (91 – 02) or (98 – 09) = 89.
(e) Product of deviation on right side is + 18 and there are two zeroes in base number 100. Therefore, two digits on the right hand side.
(f) On removing slanted line, product is 8918.

(xi) 96 × 94
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 11
Hints :
(a) Multiple 96 = 104 – 4 which is 4 less than 100 and 94 = 100 – 06 which is 6 less than 100. Write – 04 and – 06 as in form of deviation.
(b) Write numbers up and down and their deviation in front of them.
(c) Product of deviation – 4 × – 6 = 24, would be written on the right side of the diagonal line.
(d) Write on left side (96 — 6) or (94 – 4) = 90.
(e) Product of deviation on right side as + 24 and their are two zeroes in base number 100. Therefore, two digits on the right hand side.
(f) On removing (RBSESolutions.com) slanted line, product is 9024.

(xii) 98 × 104
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 12
Hints :
(a) Multiple 98 = 100 – 2 which is 2 less than 100 and 104 = 100 + 4 which is 4 more than 100. Write (- 2) and (+ 4) as in form of deviation.
(b) Write numbers up and down and their deviation in front of them.
(c) Product of deviation (- 2) × (4) = – 8, would be written on the right side of diagonal line.
(d) On left side right (98 + 4) or (104 – 2) = 102.
(e) Multiplication of deviation is negative on right hand side. For converting it into positive, take 1 from left side in form of 1 × 100 = 100, towards right hand side.
(f) 102 – 1 = 101, would be remainder in left side.
(g) On right side, 100 – 8 = 92.
(h) On removing slanted line, (RBSESolutions.com) product is 10192.

RBSE Solutions

(xiii) 85 × 93
RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.7 image 13
Hints :
(a) Multiple 85 = 100 – 15 which is less than 100 and 93 = 100 – 07 which is 7 less than 100. Write (- 15) and (- 07) as in form of deviation.
(b) Write the numbers up and down and their deviation in front of them.
(c) Product of deviation -15 × – 07 = 105, would be written on the right side of diagonal line.
(d) Write (85 – 07) or ( 93 – 15) = 78 on the left side.
(e) On the right side product of deviation is 105 (two zeroes in base 100), therefore there will be two (RBSESolutions.com) digits in right side i.e., 05. Add 1 to the left side.
(f) Now, on left side 78 + 1 = 79.
(g) On removing slanted line, product is 7905.

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