RBSE Solutions for Class 7 Maths Chapter 14 Simple Equation Ex 14.1 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 14 Simple Equation Exercise 14.1.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 7 |
| Subject | Maths |
| Chapter | Chapter 14 |
| Chapter Name | Simple Equation |
| Exercise | Ex 14.1 |
| Number of Questions | 1 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 7 Maths Chapter 14 Simple Equation Ex 14.1
Question
Solve the given below (RBSESolutions.com) equations and also verify the answer.
1. 2x + 1 = 9
2. 5x – 4 = 26
3. 5x – 2x + 7 = 31
4. 5x + 8 = 12 + 6
5. 12x + 3x = 60
6. \(\frac { 7x }{ 9 }\) = 21
7. \(\frac { 2x }{ 3 }\) – \(\frac { x }{ 2 }\) = 3
8. \(\frac { 3x }{ 4 }\) – \(\frac { 2x }{ 5 }\) = 7
9. \(\frac { 7x+1 }{ 2 }\) +1=11
10. \(\frac { 3l }{ 2 }\) = \(\frac { 2 }{ 3 }\)
11. 7m + \(\frac { 19 }{ 2 }\) = 13
12. 6z + 10 = -2
13. \(\frac { q }{ 4 }\) + 7 = 5
14. 4(2 – x) = 8
15. 3(n – 5) = 21
16. 4 = 5(t – 2)
17. 0 = 16+4(m – 6)
Solution:
1. 2x + 1 = 9
⇒ 2x = 9 – 1 = 8 (Shifting 1 to other side)
⇒ \(\frac { 2x }{ 2 }\) = \(\frac { 8 }{ 2 }\) ⇒ x = 4
Verifaction of answer LHS = 2x +1
= 2 x 4 + 1
= 8 + 1
= 9 = RHS
So, x = 4 is correct answer.
2. 5x – 4 = 26
⇒ 5x = 26 + 4 (Transferring side)
⇒ 5x = 30
⇒ \(\frac { 5x }{ 5 }\) = \(\frac { 30 }{ 5 }\) (दोनों पक्षों में 5 का भाग दने पर)
⇒ x = 6
Verifaction (RBSESolutions.com) of answer
LHS = 5x – 4
= 5 x 6 – 4 = 30 – 4
= 26 = RHS
so x = 6 is correct answer.
3. 5x – 2x + 7 = 31
3x + 7 = 31
⇒ 3x = 31 – 7 (Transferring side)
3x = 24
⇒ \(\frac { 3x }{ 3 }\) = \(\frac { 24 }{ 3 }\) (Dividing both sides by 3)
x = 8
Verifaction (RBSESolutions.com) of answer
LHS = 5x – 2x + 7
= 5 x 8 – 2 x 8 + 7
= 40 – 16 +7 = 31 = RHS
So x = 8 is correct answer.
4. 5x + 8 = 12 + 6
⇒ 5x = 18 – 8 = 10 (shifting 8 to other side)
⇒ \(\frac { 5x }{ 5 }\) = \(\frac { 10 }{ 5 }\)
(Dividing both sides by 5)
⇒ x = 2
Verifaction (RBSESolutions.com) of answer
LHS = 5x + 8
= 5 x 2 + 8 = 18
RHS = 12 + 6 = 18
So x = 2 is correct answer.
5. 12x + 3x = 60
⇒ 15 = 60
⇒ \(\frac { 15x }{ 15 }\) = \(\frac { 60 }{ 15 }\) = 4 (Dividing by 15 both sides)
⇒ x = 4
Verifaction (RBSESolutions.com) of answer
LHS = 12x + 3x = 15x
= 15 x 4 = 60 = RHS
So x = 4 is correct answer.
12. 6z + 10 = -2
⇒ 6z = -2 – 10
⇒ 6z = -12
z = – \(\frac { 12 }{ 6 }\) = -2
Verifaction of answer
LHS = 6z + 10
= 6 x (-2) + 10
= -12 + 10
= -2 = RHS
So z = -2 is correct (RBSESolutions.com) answer.
13. \(\frac { q }{ 4 }\) + 7 = 5
⇒ \(\frac { q }{ 4 }\) = 5 – 7 = -2
q = -2 x 4 = -8
Verifaction of answer
LHS = \(\frac { q }{ 4 }\) + 7 = \(\frac { -8 }{ 4 }\) + 7
= -2 +7 = 5 = RHS
So q = -8 is correct answer.
14. 4(2 – x) = 8
⇒ 2 – x = \(\frac { 8 }{ 4 }\)
⇒ 2 – x = 2
⇒ x = 2 – 2 = 0
Verifaction of answer
LHS = 4(2 – x)
= 4(2 – 0) = 8 = RHS
So x = 0 is correct answer.
15. 3(n -5) = 21
⇒ n – 5 = \(\frac { 21 }{ 3 }\) = 7
⇒ n = 7 + 5 = 12
Verifaction (RBSESolutions.com) of answer
LHS = 3(n – 5)
= 3(12 – 5) = 3(7)
= 21 = RHS
So n = 12 is correct answer.
16. 4 = 5(t – 2)
17. 0 = 16 + 4(m – 6)
⇒ 16 + 4(m – 6) = 0
⇒ 4(m – 6) = -16
⇒ m – 6 = \(\frac { -16 }{ 4 }\) = -4
⇒ m = -4 + 6 = 2
Verifaction (RBSESolutions.com) of answer
RHS = 16 + 4(m – 6)
= 16 + 4(2 – 6)
= 16 + 4(-4)
= 16 – 16 = 0 = LHS
So m = 2 is correct answer.
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