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RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions

RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 15 Comparison of Quantities Exercise Additional Questions.

BoardRBSE
TextbookSIERT, Rajasthan
ClassClass 7
SubjectMaths
ChapterChapter 15
Chapter NameComparison of Quantities
ExerciseEx 15.4
Number of Questions25
CategoryRBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions

Multiple Choice Questions

Question 1
Value of 5% is :
(A) 0.05
(B) 0.5
(C) 5
(D) 0.005

Question 2
Value of \(\frac { 1 }{ 2 }\) in (RBSESolutions.com) percentage is :
(A) 80 %
(B) 50 %
(C) 25 %
(D) 15 %

RBSE Solutions

Question 3
Express \(\frac { 4 }{ 5 }\) in ratio is :
(A) 4 : 5
(B) 5 : 4
(C) 1 : 2
(D) 2 : 3

Question 4
\(\frac { 2 }{ 3 }\) is (RBSESolutions.com) equivalent to
(A) 66\(\frac { 2 }{ 3 }\)
(B) 65\(\frac { 2 }{ 3 }\)
(C) 62\(\frac { 2 }{ 3 }\)
(D) 60\(\frac { 2 }{ 3 }\)

Question 5
Formula to find out profit percentage is :
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 1

Question 6
Formula to (RBSESolutions.com) find out % increase
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 2.

Question 7
10 % of 50 will be :
(A)10
(B) 50
(C) 40
(D) 5

Question 8
What will be value of 75% in (RBSESolutions.com) decimal fractions?
(A) 73
(B) 7.3
(C) 0.73
(D) 0.073

Question 9
Mohan purchase a pen ₹10 and sold it in ₹12. Then profit will be :
(A) ₹2
(B) ₹3
(C) ₹4
(D) ₹6

RBSE Solutions

Question 10
Suresh purchased a book in ₹120 and (RBSESolutions.com) sold it on 10% loss then its selling price is :
(A) ₹100
(B) ₹110
(C) ₹108
(D) ₹115

Answer:
(1) (A), (2) (B), (3) (A), (4) (A), (5) (B), (6) (A), (7) (D), (8) (C), (9) (A), (10) (C)

Fill in the blanks
(i) 10% of 100 will be …………..
(ii) Ratio of 2 km to 400 km will be ……………
(iii) Fraction \(\frac { 12 }{ 16 }\) is in percentage (RBSESolutions.com) form will be …………
Answer:
(i) 10,
(ii) 1 : 200,
(iii) 75%

True/False
(i) The ratio of ₹5 and 50 paise is 10 : 1.
(ii) 75% of 12 is 12\(\frac { 3 }{ 4 }\)
(iii) 35 % + 65 % = 100 %.
(iv) Fraction \(\frac { 1 }{ 8 }\) is (RBSESolutions.com) equivalent 12.5%.
Answer:
(i) True
(ii) False
(iii) True
(iv) True

Very Short Answer Type Questions

Question 1
Collection of 10 chips of various (RBSESolutions.com) colours is as follows :
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 3
Fill the table and find out the percentage of every colour chips?
Solution:
The required percentage (RBSESolutions.com) of every colour chips is as follows :
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 4

RBSE Solutions

Question 2
Find out following :
(a) 50% of 164
(b) 75% of 12
(c) 12\(\frac { 1 }{ 2 }\)% of 64
Solution:
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 5

Question 3
In the class of 25 children 8% children (RBSESolutions.com) like to wet in rain. Find out the number of children who like to wet in rain.
Solution:
Number of children who like to wet in rain = 8% of 25
= \(\frac { 8 }{ 100 }\) x 25 = 2

Question 4
9 is which number’s 25%?
Solution:
Let the number is x
25% of x = 9
⇒ \(\frac { 25 }{ 100 }\) × x = 9 ⇒\(\frac { 1 }{ 4 }\) × x = 9
⇒ x = 9 x 4 = 36
∴ Required number is 36.

Question 5
15 is which (RBSESolutions.com) number’s 75%?
Solution:
Let the number is x
75% of x = 15
⇒ \(\frac { 75 }{ 100 }\) x 1 = 15
\(\frac { 3 }{ 4 }\) x a = 15
⇒ 44 = 15 x \(\frac { 4 }{ 3 }\)
= 5 x 4 = 20
∴ Required number is 20.

Short Answer Type Questions

Question 1
In a computer lab 3 computers are required for 6 students. Find out (RBSESolutions.com) how many computers are required for 24 students?
Solution:
In a computer lab,
∵ 6 students required computers = 3
∴1 student required computers = \(\frac { 3 }{ 6 }\)
∴ 24 students required computers = \(\frac { 3 }{ 6 }\) x 24 = 3 x 4 = 12

RBSE Solutions

Question 2
Population of Rajasthan is 570 lac and population (RBSESolutions.com) of Uttar Pradesh is 1660 lac. Area of Rajasthan is 3 Lac square km and area of Uttar Pradesh is 2 lac square km.
(i) In both states how many people are per square km.
(ii) Which state is having less population density?
Solution:
(i) Population of Rajasthan = 570 lac
Area of Rajasthan = 3 lac sq. km
∴ Number of people per square km = \(\frac { 570 }{ 3 }\) = 190
And population (RBSESolutions.com) of Uttar Pradesh = 1660 lac
Area of Uttar Pradesh = 2 lac sq. km
∴ Number of people per square km
= \(\frac { 1660 }{ 2 }\)
= 830
(ii) Because per square km less people are living in Rajasthan. So, Rajasthan is having less population density.

Question 3
Find out
(a) 15% of 250
(b) 1% of an hour
(c) 20% of 2500
(d) 75% of 1kg
Solution:
(a) 15% of 250 = \(\frac { 15 }{ 100 }\) x 250
= 15 x 2.5 = 37.5

(b) 1% of 1 hour = 1% of 60 minutes
= \(\frac { 1 }{ 100 }\) x 60 = \(\frac { 6 }{ 100 }\) minutes
= \(\frac { 6 }{ 10 }\) x 60 second = 36 second

(c) 20% of 2500 = \(\frac { 20 }{ 100 }\) x 2500
= 20 x 25 = 500

(d) 75% of 1 kg = 75% of 1000 gm
= \(\frac { 75 }{ 100 }\) x 1000 = 750 gm = 0.75 kg.

Long Answer Type Questions

Question 1
In chalk powder calcium, carbon and oxygen (RBSESolutions.com) ratio are 10 : 3 : 12. Find out the carbon percentage.
Solution:
Calcium : Carbon : Oxygen
10 : 3 : 12
Total of ratio = 10 + 3 + 12 = 25
Parts of carbon in chalk = \(\frac { 3 }{ 25 }\)
∴ Percentage of carbon in chalk = ( \(\frac { 3 }{ 25 }\) x 100)%
= (3 x 40)%
= 12%

Question 2
Amina purchase a book in ₹275 and sold it on 15 percent loss, then (RBSESolutions.com) find out the selling price of the book.
Solution:
C.P. of book = ₹275
Loss = 15%
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 6

Question 3
In every condition after 3 years how much amount (RBSESolutions.com) has to be paid if principal = ₹1200, rate = 12% P.A.
Solution:
Principal = ₹1200, Rate = 12%. Time = 3 years
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 7

Question 4
Arun purchased a car in ₹3,50,000 and next year its price (RBSESolutions.com) has increased up to ₹3,70,000. Find the percentage increase in the price of car.
Solution:
Original Price = ₹3,50,000
Increased Price = ₹3,70,000
Increment in Price = ₹(3,70,000 – 3,50,000)
= ₹20,000
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 8

RBSE Solutions

Question 5
I have purchased a T.V. in ₹10,000 and taking 20% profit it has (RBSESolutions.com) been sold out. How much money I received on selling of this ?
Solution:
C.P. = ₹10,000, Profit = 20%
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 9

Question 6
On selling a washing machine in ₹13500, Juhi bears a loss of 20%. What was (RBSESolutions.com) the cost price of washing machine?
Solution:
S.P. = ₹13,500, loss = 20%
RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions - 10
∴ C.P. of washing machine = ₹16,875

We hope the RBSE Solutions for Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 15 Comparison of Quantities Additional Questions, drop a comment below and we will get back to you at the earliest.

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