RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.2

RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.2 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.2.

Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.2

Question 1
Match appropriate product (RBSESolutions.com) with line diagrams:

Solution:
(i) (b),
(ii) (c),
(iii) (a)

Question 2
Show the following figures in (RBSESolutions.com) terms of multiplication (repeated addition) :

Solution:

Question 3
Multiply and express (RBSESolutions.com) In the simplest form:

Solution:

Question 4
Shade the (RBSESolutions.com) following:
(i) Colour the \(\frac { 1 }{ 2 }\) Part of the circles in box (a).
(ii) Colour the \(\frac { 2 }{ 3 }\) Part of the triangles in box (b).
(iii) Colour the \(\frac { 1 }{ 5 }\) part of the rectangles in box (c).

Solution:

Question 5
Find the (RBSESolutions.com) following:


Solution:

Question 6
Find:

Solution:

Question 7
Multiply the (RBSESolutions.com) following fractions

Solution:

Question 8
Which is (RBSESolutions.com) greater?

Solution:

we know if numerators of fractions (RBSESolutions.com) are equal then the fraction having shorter denominator is greater.

Question 9
Manisha took 15 litres milk for (RBSESolutions.com) selling It out. She sold \(\frac { 2 }{ 5 }\) part of milk to Kanchan and \(\frac { 1 }{ 5 }\) part of milk to Bhawna and remaining part to a hotel. Find
(i) How much milk she sold to Kanchan?
(ii) How much milk she sold to Bhawna?
(ill) How much milk she sold to hotel?
Solution:
Total milk = 15 L
(i) Quantity of milk given to Kanchan house
= 15 x \(\frac { 2 }{ 5 }\) = \(\frac { 15\times 2 }{ 5 }\) = 3 x 2 = 6 L
(ii) Quantity of milk given to Bhavna’s house
= 15 x \(\frac { 1 }{ 5 }\) = 3 x 1 = 3L
(iii) Quantity of miLk sold on hotel
= 15 – (6 + 3) = (15 -9 ) = 6L.

Question 10
7 boys were placed each \(\frac { 3 }{ 4 }\) meter (RBSESolutions.com) apart from the other for PT demonstration on independence day. What is the distance between the first and the last boy?
Solution:
Let 7 children A, B, C, D, E, F and G are standing

AB= BC = CD = DE = EF = FG = \(\frac { 3 }{ 4 }\)m
∴Distance between frist and last children
= AG = 6 × AB
= 6 × \(\frac { 3 }{ 4 }\)
= \(\frac { 3\times 3 }{ 2 }\) = \(\frac { 9 }{ 2 }\) m

Question 11
Rahul works on a painting 2 hours daily. If he (RBSESolutions.com) takes 8 days to complete this painting then calculate the number of hours he worked.
Solution:
Rahul ‘s one day work = 2\(\frac { 3 }{ 4 }\) = \(\frac { 11 }{ 4 }\)hrs
∴ Rahul’s 8 days work =\(\frac { 11 }{ 4 }\) x 8
= 11 x 2 = 22 hrs.

Question 12
A car travel 23\(\frac { 1 }{ 5 }\) km using 1 litre petrol. What (RBSESolutions.com) distance will it travel using 2\(\frac { 3 }{ 4 }\) litre petrol?
Solution:
∵ Distance covered by car in I litre petrol
= 23\(\frac { 1 }{ 5 }\) km = \(\frac { 116 }{ 5 }\) km
∴ Car will cover the distance in 2\(\frac { 3 }{ 4 }\) litre petrol

Question 13
(i) Write the (RBSESolutions.com) number in the box so that

(ii) The simplest form of number in the box is……
Solution:
Let the number written in  is x.

(ii) Number received in  is \(\frac { 2 }{ 10 }\)
∴ Simplest form of \(\frac { 2 }{ 10 }\) = \(\frac { 2\times 1 }{ 2\times 5 }\) = \(\frac { 1 }{ 5 }\)

Question 14
(i) Write the number in (RBSESolutions.com) the box so that

(ii) The simplest form of number In the box of (i) is ……
Solution:
Let the number written in  is x.

(ii) Simplest form of number written in  = \(\frac { 2 }{ 3 }\)

We hope the RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.2 will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.2, drop a comment below and we will get back to you at the earliest.