RBSE Solutions for Class 7 Maths Chapter 5 Powers and Exponents Ex 5.1

RBSE Solutions for Class 7 Maths Chapter 5 Powers and Exponents Ex 5.1 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 5 Powers and Exponents Exercise 5.1.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 7
Subject	Maths
Chapter	Chapter 5
Chapter Name	Powers and Exponents
Exercise	Ex 5.1
Number of Questions	6
Category	RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 5 Powers and Exponents Ex 5.1

Question 1
Express the following in (RBSESolutions.com) terms of exponents
(i) 7 x 7 x 7 x 7 x 7
(it) 3 x 3 x 3 x 7 x 7
(iii) a x a x a x b x b
(iv) 5 x 5 x t x t x t
Solution:
(i) 7 x 7 x 7 x 7 x 7 = 7⁵
(ii) 3 x 3 x 3 x 7 x 7 = (3 x 3 x 3) x (7 x 7) = 3³ x 7²
(iii) a x a x a x b x b = (a x a x a) x (b x b) = a³ x b²
(iv) 5 x 5 x t x t x t = (5 x 5) x (t x t x t) = 5² x t³

Question 2
Express each of the following (RBSESolutions.com) number in the form of exponents :
(i) 32
(ii) 81
(iii) 343
(iv) 125
Solution:
(i) 32 = 2 x 2 x 2 x 2 x 2 = 2⁵

(ii) 81 = 3 x 3 x 3 x 3 = 3⁴

(iii) 343 =7 x 7 x 7 = 7³

(iv) 125 = 5 x 5 x 5 = 5³

Question 3
Identify the greater (RBSESolutions.com) number in the following:
(i) 2⁵ or 5²
(ii) 3⁵ or 5³
(iii) 3¹⁰ or 10³
(iv) 7³ or 3⁷
Solution:
(i) 2² or 5²
2⁵ = 2 x 2 x 2 x 2 x 2 = 32
and 5² = 5 x 5 = 25
Clearly 32 > 25 ⇒ 2⁵ > 5²
अतः 2⁵ greater (RBSESolutions.com) number

(ii) 3⁵ or 5³
3⁵ = 3 x 3 x 3 x 3 x 3 = 243
and 5³ = 5 x 5 x 5 = 125
Clearly 243 > 125 or 3⁵ > 5³
∴ 3⁵ greater number

(iii) 3¹⁰ or 10³
3¹⁰ = 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3
= 243 x 243 = 59049
and 10³ = 10 x 10 x 10 = 1000
Clearly 59049 >1000 or 3¹⁰ > 10³
∴ 3¹⁰ greater (RBSESolutions.com) number

(iv) 7³ or 3⁷
∴ 7³ = 7 x 7 x 7 = 343
and 3⁷ =3 x 3 x 3 x 3 x 3 x 3 x 3 = 2187
Clearly 2187 > 343 or 3⁷ > 7³
∴ 3⁷ greater number.

Question 4
Express the following (RBSESolutions.com) numbers in terms factors :
(i) 324
(ii) 625
(iii) 1080
(iv) 1800
Solution:
(i) On factorizing by division method

∴ 324 = 2 x 2 x 3 x 3 x 3 x 3
= 2² x 3⁴

(ii) On factorizing by (RBSESolutions.com) division method

∴ 625 = 5 x 5 x 5 x 5
= 5⁴

(iii) On factorizing by division method

∴1080 = 2 x 2 x 2 x 3 x 3 x 3 x 5
= 2³ x 3³ x 5

(iv) On factorizing by (RBSESolutions.com) division method

∴ 1800 = 2 x 2 x 2 x 3 x 3 x 3 x 5
= 2³ x 3² > 5²

Question 5
Simplify the (RBSESolutions.com) following :
(i) 2 x 3⁴
(ii) 7³ x 5
(iii) 5³ x 2²
(iv) 3² x 10²
(v) 0 x 10⁴
Solution:
(i) 2 x 3⁴ = 2 x 3 x 3 x 3 x 3 = 162
(ii) 7³ x 5 = 7 x 7 x 7 x 5 = 1715
(iii) 5³ x 2² = 5 x 5 x 5 x 2 x 2 = 500
(iv) 3² x 10³ = 3 x 3 x 10 x 10 x 10 = 9000
(v) 0 x 10⁴ = 0 x 10 x 10 x 10 x 10 = 0

Question 6
Find the (RBSESolutions.com) values of:
(i) (-1)³
(ii) (- 5)⁴
(iii) (-4)² x (-2)³
Solution:
(i) (-1)³ = (-1) x (-1) x (-1) = -1
(ii) (-5)⁴ = (-5) x (-5) x (-5) x (-5) = 625
(iii) (-4)² x (-2)³ = (-4) x (-4) x (-2) x (-2) x (-2) = – 128

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