RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics Ex 6.5

RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics Ex 6.5 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 6 Vedic Mathematics Exercise 6.5.

Rajasthan Board RBSE Class 7 Maths Chapter 6 Vedic Mathematics Ex 6.5

Question 1

Solution:

Question 2

Solution:

Sum of extreme (RBSESolutions.com) digits \(\frac { 1 }{ 2 }\), \(\frac { 1 }{ 2 }\)
(i) Sum of charma digits = \(\frac { 1 }{ 2 }\) + \(\frac { 1 }{ 2 }\) = \(\frac { 1+1 }{ 2 }\) = \(\frac { 2 }{ 2 }\) = 1
(ii) Shesh nikhilam ank are equal to each other = 5
(iii) L.H.S = First Part = Shesh nikhilam ank x one more shesh nikhilam ank
(iv) R.H.S = second part = Product of charamank

Question 3

Solution:

Question 4

Solution:

Question 5
\(12\frac { 1 }{ 4 } \times 12\frac { 3 }{ 4 }\)
Solution:

Question 6
\(8\frac { 2 }{ 7 } \times 8\frac { 5 }{ 7 }\)
Solution:

Question 7
\(3\frac { 1 }{ 4 } \times 4\)
Solution:

Question 8
\(2\frac { 1 }{ 5 } \times 5\)
Solution:

Question 9
\(3\frac { 1 }{ 2 } \times 4\)
Solution:

Question 10
\(4\frac { 1 }{ 3 } \times 6\)
Solution:

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