RBSE Solutions for Class 8 Maths Chapter 1 Rational Numbers Ex 1.1 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 1 Rational Numbers Exercise 1.1.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 8 |
| Subject | Maths |
| Chapter | Chapter 1 |
| Chapter Name | Rational Numbers |
| Exercise | Exercise 1.1 |
| Number of Questions | 11 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 8 Maths Chapter 1 Rational Numbers Ex 1.1
RBSE Class 8 Maths Chapter 1 Question 1.
Add the following rational numbers. (Solve any two on number line)
Solution:
Distance between two consecutive numbers on number line is \(\frac { 1 }{ 4 }\)
So,addition of \(\frac { -3 }{ 4 }\) with \(\frac { 5 }{ 2 }\) means, addition of \(\frac { -3 }{ 4 }\) with \(\frac { 10 }{ 4 }\)
We have to move three gaps from \(\frac { 10 }{ 4 }\) in left side (being negative(RBSESolutions.com) sign of \(\frac { -3 }{ 4 }\))
So, we reach finally at \(\frac { 7 }{ 4 }\)
Distance gap between two(RBSESolutions.com)consecutive points on number line is \(\frac { 1 }{ 3 }\). Therefore, addition of \(\frac { -2 }{ 3 }\) with 0 means, we have to move 2 gaps in left side from zero, so we reach finally at \(\frac { -2 }{ 3 }\)
Hence, 0 + \(\frac { -2 }{ 3 }\) = \(\frac { -2 }{ 3 }\)
RBSE Solutions For Class 8 Maths Chapter 1 Question 2.
Find the value (Solve any two on number line)-
Solution:
Distance between two points (gaps) on number line is \(\frac { 1 }{ 12 }\)
So, addition of \(\frac { 8 }{ 12 }\) and \(\frac { 15 }{ 12 }\) means we have to move 15 gaps in right side (being positive sign of \(\frac { 8 }{ 12 }\) So, we reach at \(\frac { 23 }{ 12 }\) finally.
Solution on number line-
Distance(RBSESolutions.com)between two points (gaps) on
Number line is \(\frac { 1 }{ 63 }\)
\(\frac { -7 }{ 63 } +\left( \frac { -5 }{ 21 } \right) =\left( \frac { -7 }{ 63 } \right) +\left( \frac { -15 }{ 63 } \right) \)
S0, addition of \(\frac { -7 }{ 63 }\) and \(\frac { -15 }{ 63 }\) means we have to move 15 gaps in left side negative sign of \(\frac { -7 }{ 63 }\) So, we reach at \(\frac { -22 }{ 63 }\) finally.
Hence \(\frac { -7 }{ 63 } +\left( \frac { -5 }{ 21 } \right) =\frac { -22 }{ 63 } \)
RBSE Solutions For Class 8 Maths Question 3.
Multiply the following rational numbers-
Solution:
Class 8 Maths RBSE Solution Question 4.
Find the values
Solution:
RBSE Solution Class 8 Maths Question 5.
Find the values
Solution:
RBSE Solutions Class 8 Maths Question 6.
Find the value of the(RBSESolutions.com)following using the appropriate properties
Solution:
RBSE Solutions For Class 8 Maths 2021 Question 7.
Find the additive inverse of the following rational numbers
Solution:
RBSE Solutions For Class 8 Question 8
Find multiplicative inverse of the following rational numbers
Solution:
(i) – 17
RBSE Solutions Class 8 Question 9.
Multiply the rational number \(\frac { 5 }{ 7 }\) to inverse of \(\frac { -7 }{ 15 }\)
Solution:
Class 8 Maths Chapter 1 Exercise 1.1 Solutions Question 10.
Fill in the blanks—
(i) Product of two rational number is always ___(Rational/Integers)
(ii) Additive(RBSESolutions.com)inverse of any negative rational number is ___(positive/negative)
(iii) Inverse of zero is ___(zero/In determined)
(iv) Additive identity of rational number is ___(zero/one)
(v) Multiplicative identity of rational number is ____(zero/one)
(vi) Reciprocal of rational number is ___of that. (inverse/same)
(vii) Negative(RBSESolutions.com)rational number on number line is always lies on ____ of zero (right/left)
(viii) Positive rational number on number line is always lies on ___ of zero. (right/left)
(ix) When rational number is added with its additive inverse then result is always ___(zero/same)
(x) When rational number is divided by same rational number then result is always ____(zero/one)
Solution:
(i) Rational
(ii) positive
(iii) undefined
(iv) zero
(v) one
(vi) reciprocal
(vii) left
(viii) right
(ix) zero
(x) one.
Class 8th Math Exercise 1.1 Question 11.
By mean method-
(i) Write any five rational numbers between – 3 and 0.
(ii) Write an(RBSESolutions.com)four rational numbers larger than 0 and smaller than \(\frac { 5 }{ 6 }\)
(iii) Find any three rational numbers between \(\frac { -3 }{ 4 }\) and \(\frac { 5 }{ 6 }\)
Solution:
(i) Rational number between – 3 and 0
(ii) Rational number between 0 and \(\frac { 5 }{ 6 }\)
(iii) Rational number between \(\frac { -3 }{ 4 }\) and \(\frac { 5 }{ 6 }\)
We hope the given RBSE Solutions for Class 8 Maths Chapter 1 Rational Numbers Ex 1.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 1 Rational Numbers Exercise 1.1, drop a comment below and we will get back to you at the earliest.