RBSE Solutions for Class 8 Maths Chapter 9 Algebraic Expressions Ex 9.1 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 9 Algebraic Expressions Exercise 9.1.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 8 |
| Subject | Maths |
| Chapter | Chapter 9 |
| Chapter Name | Algebraic Expressions |
| Exercise | Exercise 9.1 |
| Number of Questions | 4 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 8 Maths Chapter 9 Algebraic Expressions Ex 9.1
Question 1.
Find the product of the following pairs of monomials.
(i) 3 × 5x
(ii) – 5p, – 2q
(iii) 7l², – 3n²
(iv) 6m, 3n
(v) – 5x², – 2x
Solution
(i) 3 × 5x
= 3 × 5 × x
= 15x
(ii) – 5p,- 2q
= (- 5) × p × (- 2) × q
= (- 5) × (- 2) × p × q
= 10pq
(iii) 7l², – 3n²
= 7 × l² × (- 3) × n²
= 7 × (- 3) × l² × n²
= – 21l²n²
(iv) 6m, 3n
= 6 × m × 3 × n
= 6 × 3 × m × n
= 18 mn
(v) – 5x², – 2x
= (- 5) × x² × (- 2) × x
= (- 5) × (- 2) × x² × x
= 10x³
Question 2.
Complete the table.
| X | 7 | x | y | 2z | a | -5b | c |
| 7 | 49 | ||||||
| x | |||||||
| 2y | |||||||
| -3a | -3ay | ||||||
| b | |||||||
| y | |||||||
| 2x3 | |||||||
| a4 | a5 | ||||||
| z2 |
Solution
| X | 7 | x | y | 2z | a | -5b | c |
| 7 | 49 | 7x | 7y | 14z | 7a | -35b | 7c |
| x | 7x | x2 | xy | 2zx | ax | -5bx | cx |
| 2y | 14y | 2xy | 2y2 | 4yz | 2ay | -10by | 2cy |
| -3a | -21a | -3ax | -3ay | -6az | -3a2 | 15ab | -3ac |
| b | 7b | bx | by | 2bz | ab | -5b2 | bc |
| y | 7y | xy | y2 | 2yz | ay | -5by | cy |
| 2x3 | 143 | 2x4 | 2x3y | 4x3z | 2x3a | -10x3b | 2x3c |
| a4 | 7a4 | a4x | a4y | 2a4z | a5 | -5a4b | a4c |
| z2 | 7z2 | xz2 | yz2 | 2z3 | az2 | -5bz2 | cz2 |
Question 3.
Multiply the following monomials
(i) xy, x²y, xy, x
(ii) m, n, mn, m3n, mn3
(iii) kl, lm, km, klm
Solution
(i) xy, x²y, xy, x
xy × x²y × xy × x
= x × y × x × x × y × x × y × x
= x × x × x × x × x × y × y × y
= x5 × y3
= x5y3
(ii) m, n, mn, m3n, mn3
m × n × mn × m3n × mn3
= m × n × m × n × m × m × m × n ×m × n × n × n
= m × m × m × m × m × m × n × n × n × n × n × n
= m6 × n6
= m6n6
(iii) kl, lm, km, klm
kl × lm × km × klm
= k × l × l × m × k × m × k × l × m
= k × k × k × l × l × l × m × m × m
= k3 × l3 × m3
= k3l3 × m3
= k3l3m3
Question 4.
Find the simple interest = \(\frac { PTR }{ 100 }\), If principal (P) = 4x², time (T) = 5x and rate of interest (R) = 5y.
Solution
Simple Interest = \(\frac { PTR }{ 100 }\)
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