RBSE Solutions for Class 9 Maths Chapter 1 Vedic Mathematics Ex 1.2 is part of RBSE Solutions for Class 9 Maths. Here we have given RBSE Rajasthan Board Solutions for Class 9 Maths Chapter 1 Vedic Mathematics Ex 1.2.

Board |
RBSE |

Class |
Class 9 |

Subject |
Maths |

Chapter |
Chapter 1 |

Chapter Name |
Vedic Mathematics |

Exercise |
Ex 1.2 |

Number of Questions Solved |
27 |

Category |
RBSE Solutions |

## RBSE Solutions for Class 9 Maths Chapter 1 Vedic Mathematics Ex 1.2

**Change the following into Vinculum numbers:**

Question 1.

89

Solution:

Question 2.

878

Solution:

Question 3.

9687

Solution:

Question 4.

6578

Solution:

Question 5.

\(3\bar { 2 } 1\)

Solution:

Question 6.

\(2\bar { 4 } \bar { 3 } \bar { 2 } \)

Solution:

Question 7.

\(4\bar { 3 } 0\bar { 2 } \)

Solution:

Question 8

\(450\bar { 4 } \bar { 9 } \)

Solution:

Question 9.

102 x 107

Solution:

102 x 107

(i) Base = 100

(ii) Deviations (RBSESolutions.com) from base 100 = +2, +7

Question 10.

94 x 92

Solution:

94 x 92

(i) Base =10, sub base = 10 x 9 = 90

(ii) Deviations from sub-base = +4, +2

(iii) In L.H.S the (RBSESolutions.com) multiplication of sub base digits = 864.

Question 11.

71 x 73

Solution:

71 x 73

Question 12.

203 x 204

Solution:

203 x 204

Question 13.

11 x 12 x 13

Solution:

11 x 12 x 13

= 11 + 2 + 3/ 2 + 6 + 3/1 x 2 x 3 = 16 /_{1} 1 / 6

= 1716

Question 14.

97 x 98 x 99

Solution:

97 x 98 x 99

= 97 – 2 – 1 / 6 + 2 + 3 / (-3) (-2) (-1)

= 94 / 11 / \(\bar { 06 } \)

= 94 / 11 – 1 / \(\bar { 06 } \)

= 94 / 10 / 100 – 06

= 941094

Question 15.

102 x 103 x 104

Solution:

102 x 103 x 104

= 102 + 03 + 04 / 6 + 12 + 8 / 2 x 3 x 4

= 109 / 26 / 24

= 1092624

Question 16.

99 x 101 x 103

Solution:

99 x 101 x 103

= 99 + 1 + 3 / 3 – 1 – 3 / (-1) (+1) (+3)

= 103 / (-1) / (-3)

= 103 – 1 / (- 1) / (- 3)

= 102 / 100 – 1 / (- 3)

= 102 / 99 / (- 3)

= 102 / 99 – 1 / – 3

= 102 / 98 / 100 – 3

= 102 / 98 / 97

= 1029897

**Find the square of the following numbers**

Question 17.

103

Solution:

103² = 103 + 03 / (03)²

= 106 / 09 = 10609

Question 18.

95

Solution:

95² = 95 – 05 / (-05)²

Here deviation = (- 5)

= 90 / 25 = 9025

Question 19.

204

Solution:

204² = 2 (204 + 4) / (04)²

= 2 (208) / 16

= 416 / 16

= 41616

Question 20.

225

Solution:

225² = 2 (225 + 25) / 25²

= 2 (250) / 625

= 500 /_{6} 25

= 50625

**Find the cube of the following numbers**

Question 21.

15

Solution:

15^{3} = 15 + 2 x (5) / 3 x (5)^{2} / 5^{3}

[Base = 10, deviation = 5] = 25 / 75 / 125 = 25 / 75 /_{12} 5

= 25 / 87 / 5 = 25 /_{8} 7 / 5 = 33 / 7 / 5

Question 22.

91

Solution:

91^{3}

= 91 + 2 x (-09) / 3 x (-09)^{2} / (-09)^{3}

[Base = 100, deviation = (-09)]

= 73 / 243 / (-729)

= 73 /_{2} 43 / (-729)

= 75 / 43 / -729

= 754300 – 729

= 753571

Question 23.

32

Solution:

32^{3} = 3^{2} (32 + 2 x 2) / 3 x 3 x (2)^{2} / 2^{3}

[Base =10, sub-base = 3, deviation = 2]

= 9 x 36/9 x 4/8

= 324 / 36 / 8

= 324 /_{3} 6 / 8

= 327 / 6 / 8

= 32768

Question 24.

208

Solution:

208^{3} = 2^{2} (208 + 2 x 8)/2 x 3 x (8)^{2} / (8)^{3}

[Base = 100, sub-base = 2, deviation = 8]

= 4 (224) / 384 / 512

= 896 /_{3} 84 / 512

= 899 / 84 /_{5} 12

= 899 / 89 / 12

= 8998912

**Divide the following by using Nikhiiam Sutra**

Question 25.

1245 ÷ 97

Solution:

1245 ÷ 97 Here (RBSESolutions.com) base is 100

Quotient = 12 and Remainder = 81

Question 26.

311 ÷ 8

Solution:

311 ÷ 8

Hints:

(i) quotient = 37, remainder =15

(ii) ∵ remainder > divisor

∴ correction (RBSESolutions.com) is necessary

∴ corrected quotient = 38

corrected remainder = 7

Question 27.

1013 ÷ 88

Solution:

1013 ÷ 88 Here base is 100

Quotient = 11, remainder = 45

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