# RBSE Solutions for Class 9 Maths Chapter 13 Angles and their Measurement

RBSE Solutions for Class 9 Maths Chapter 13 Angles and their Measurement is part of RBSE Solutions for Class 9 Maths. Here we have given Rajasthan Board RBSE Class 9 Maths Solutions Chapter 13 Angles and their Measurement.

 Board RBSE Textbook SIERT, Rajasthan Class Class 9 Subject Maths Chapter Chapter 13 Chapter Name Angles and their Measurement Exercise Ex 13 Number of Questions Solved 15 Category RBSE Solutions

## Rajasthan Board RBSE Class 9 Maths Solutions Chapter 13 Angles and Their Measurement

Multiple Choice Questions

Question 1.
The line describing (RBSESolutions.com) an angle of 750°, lies in:

Question 2.
The number of radians in angle 30° is:
(A) $$\frac { \pi }{ 3 }$$ radian
(B) $$\frac { \pi }{ 4 }$$ radian
(C) $$\frac { \pi }{ 6 }$$ radian
(D) $$\frac { 3\pi }{ 4 }$$ radian Question 3.
The value of $$\frac { 3\pi }{ 4 }$$ in sexagesimal system is:
(A) 75°
(B) 135°
(C) 120°
(D) 220°

Question 4.
The time taken by the minute hand of (RBSESolutions.com) a watch in tracing an angle of $$\frac { \pi }{ 6 }$$ radians is:
(A) 10 minutes
(B) 20 minutes
(C) 15 minutes
(D) 5 minutes

Question 5.
The value of the angle, in radian subtended at the centre of the circle of radius 100 metres by an arc of length 25π metres is:
(A) $$\frac { \pi }{ 4 }$$
(B) $$\frac { \pi }{ 3 }$$
(C) $$\frac { \pi }{ 6 }$$
(D) $$\frac { 3\pi }{ 4 }$$

1. A
2. C
3. B
4. D
5. A

Question 6.
In which quadrant does the (RBSESolutions.com) revolving ray lie when it makes the following angles.
(i) 240°
(ii) 425°
(iii) – 580°
(iv) 1280°
(v) – 980°
Solution.
(i) 240° = 2 x right angle + 60°, therefore the position of the revolving ray will be in third quadrant.
(ii) 425° = 4 x right angles + 65°, therefore the position of the revolving ray will be in first quadrant.
(iii) – 580° = – 6 x right angles – 40°, therefore the position of the revolving ray will be in second quadrant.
(iv) 1280° = 14 x right angles + 20°, therefore the position of the revolving ray will be in third quadrant.
(v) – 980° = – 10 x right angles – 80°, therefore the position of the revolving ray will be in second quadrant.

Question 7.
Convert the following angles (RBSESolutions.com) in radians:
(i) 45°
(ii) 120°
(iii) 135°
(iv) 540°
Solution.  Question 8.
Express the following angles (RBSESolutions.com) in sexagesimal system.
(i) $$\frac { \pi }{ 2 }$$
(ii) $$\frac { 2\pi }{ 5 }$$
(iii) $$\frac { 5\pi }{ 6 }$$
(iv) $$\frac { \pi }{ 15 }$$
Solution. Question 9.
Find the angle in radians subtended at the centre of (RBSESolutions.com) a circle of radius 5 cm by an arc of the circle whose length is 12 cm.
Solution.
We know that:
θ (radian) = $$\frac { arc length }{ radius }$$
We have, radius = 5 cm
and arc length = 12 cm
θ = $$\frac { 12 }{ 5 }$$

Question 10.
How much time the minute hand of a watch will take to describe an angle of $$\frac { 3\pi }{ 2 }$$ radians.
Solution.
Time taken by the minute hand of a watch in tracing 4 right angles or an angle equal to 2it radians = 1 hour.
Time taken by the minute hand of a clock in tracing an angle equal to 1 radian = $$\frac { 1 }{ 2\pi }$$ hours
Time taken by the minute hand of a clock in tracing an angle equal to $$\frac { 3\pi }{ 2 }$$ radians
= $$\frac { 1 }{ 2\pi } \times \frac { 3\pi }{ 2 }$$ hours
= $$\frac { 3 }{ 4 }$$ hours or 45 minutes 4

Question 11.
How much time the minute hand of a watch will take (RBSESolutions.com) to describe an angle of 120°?
Solution.
We know that:
The minute hand of a watch describes an angle of 4 right angles i.e. 360° in one hour.
the time taken by minute hand to trace an angle of 1° = $$\frac { 1 }{ 360 }$$ hours
the time taken by minute hand to trace 120° angle
= $$\frac { 1 }{ 360 }$$ x 120
= $$\frac { 1 }{ 3 }$$ hours
= $$\frac { 1 }{ 3 }$$ x 60 minutes
= 20 minutes.

Question 12.
Find the radius of the circle, if any arc length of 10 cm subtends (RBSESolutions.com) an angle of 60° at the centre of the circle.
Solution. Question 13.
Find the time if the minute hand of a clock (RBSESolutions.com) has revolved through 30 right angles just after noon.
Solution.
We know that:
The time taken by the minute hand of a clock in tracing 4 right angles is 1 hour.
So, we convert 30 right angles in terms of the multiple of 4 right angles
i.e. 30 right angles
= 7 x (4 right angles) + 2 right angles
= 7 x 1 hr + $$\frac { 1 }{ 2 }$$ hr = 7$$\frac { 1 }{ 2 }$$ hours
= 7 hours 30 minutes
Hence, time = 7 : 30 p.m. Question 14.
The angles of a triangle are in (RBSESolutions.com) the ratio of 2 : 3 : 4. Find all the three angles in radians.
Solution.
The A, B and C are angles of any triangle ABC
A : B : C = 2 : 3 : 4
⇒ ∠A = 2x, ∠B = 3x and ∠C = 4x
∠A + ∠B + ∠C = 180° (Angles sum property of a triangle)
⇒ 2x + 3x + 4x = 180°
⇒ 9x = 180°
⇒ x = 20°
Therefore angles (in degrees) are 40°, 60′ and 80°  Question 15.
Convert $$\frac { 3\pi }{ 5 }$$ radian into (RBSESolutions.com) sexagesimal system.
Solution. We hope the given RBSE Solutions for Class 9 Maths Chapter 13 Angles and their Measurement will help you. If you have any query regarding Rajasthan Board RBSE Class 9 Maths Solutions Chapter 13 Angles and their Measurement, drop a comment below and we will get back to you at the earliest.