RBSE Solutions for Class 9 Maths Chapter 14 Trigonometric Ratios of Acute Angles Ex 14.2 is part of RBSE Solutions for Class 9 Maths. Here we have given Rajasthan Board RBSE Class 9 Maths Solutions Chapter 14 Trigonometric Ratios of Acute Angles Ex 14.2.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 9 |

Subject |
Maths |

Chapter |
Chapter 14 |

Chapter Name |
Trigonometric Ratios of Acute Angles |

Exercise |
Exercise 14.2 |

Number of Questions Solved |
10 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 9 Maths Solutions Chapter 14 Trigonometric Ratios of Acute Angles Ex 14.2

**Solve the following by using trigonometric identities (1 to 10)**

Question 1.

If cosec A = \(\frac { 5 }{ 4 }\), then (RBSESolutions.com) evaluate cot A, sin A and cos A.

Solution.

Question 2.

If tan A = \(\frac { 20 }{ 21 }\), then (RBSESolutions.com) evaluate cos A and sin A.

Solution.

Question 3.

If sin A = \(\frac { 3 }{ 5 }\), then (RBSESolutions.com) evaluate cos A and tan A.

Solution.

Question 4.

If cos B = \(\frac { 1 }{ 4 }\), then find (RBSESolutions.com) the remaining trigonometrical ratios.

Solution.

Question 5.

If sin A = \(\frac { 5 }{ 13 }\), then (RBSESolutions.com) evaluate cos A and tan A.

Solution.

Question 6.

If tan A = √2 – 1, then prove that sin A cos A = \(\frac { 1 }{ 2\surd 2 }\)

Solution.

Question 7.

If tan A = 2, then (RBSESolutions.com) evaluate sec A . sin A + tan^{2}A – cosec A.

Solution.

tan A = 2 (given)

Question 8.

If sin θ = \(\frac { 4 }{ 5 }\) then (RBSESolutions.com) evaluate \(\frac { 4tan\theta -5cos\theta }{ sec\theta +4cos\theta }\)

Solution.

Question 9.

If cos θ = \(\frac { 1 }{ \surd 2 }\), then (RBSESolutions.com) evaluate sin θ and cot θ

Solution.

Question 10.

If sec θ = 2, then evaluate tan θ, cos θ and sin θ.

Solution.

sec θ = 2 (given)

We know that 1 + tan^{2}θ = sec^{2}θ

tan^{2}θ = sec^{2}θ – 1

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