RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.2 is part of RBSE Solutions for Class 9 Maths. Here we have given Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Ex 8.2.

Board |
RBSE |

Class |
Class 9 |

Subject |
Maths |

Chapter |
Chapter 8 |

Chapter Name |
Construction of Triangles |

Exercise |
Ex 8.2 |

Number of Questions Solved |
4 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Ex 8.2

**Case II: To construct a triangle whose two sides and included angle is given.**

Question 1.

Construct a triangle ABC where a = 4 cm, b = 5 cm and ∠C = 60°.

Solution.

Steps of construction:

- Draw b = 5 cm as base.

- With C as centre, draw (RBSESolutions.com) an angle of 60° with the help of compass.
- With centre C, take an arc of radius 4 cm and cut it.
- Join B to A.

Hence, ABC is the required triangle.

Question 2.

Construct a triangle LMN where ∠L =120°, LM = 4 cm and LN = 5 cm.

Solution.

Steps of construction:

- Draw base LM = 4 cm.

- With L as centre, draw an angle of 120° with the help of compass.
- With L as centre, draw an arc of (RBSESolutions.com) radius 5 cm which cuts the line segment at N.
- Join MN.

Hence, ∆LMN is the required triangle.

Question 3.

Construct a ∆ABC where AB = AC = 8 cm, ∠A = 15°. Draw a bisector of ∠B which meets the opposite side.

Solution.

Steps of construction:

- Draw AB = 8 cm as base.

- At A draw an angle of 75°.
- Now taking A as centre, draw (RBSESolutions.com) an arc of radius 8 cm which cuts the arm of the angle 75° at C. Join C to B.
- Now draw angle bisector of ∠B which meets the opposite side AC at E (suppose).

Hence, ∆ABC is the required triangle.

Question 4.

Construct an isosceles triangle whose vertex angle is 120° and each of equal sides are 5.5 cm in length.

Solution.

Steps of construction:

- Draw one of the equal side BC at 5.5 cm.

- With B as centre, draw vertex angle 120°.
- With centre B, draw an arc of radius 5.5 cm, which (RBSESolutions.com) cuts at the point A.
- Join BA and CA.

Hence, ∆ABC is the required isosceles triangle whose vertex ∠B = 120°.

We hope the given RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.2 will help you. If you have any query regarding RBSE Rajasthan Board Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.2, drop a comment below and we will get back to you at the earliest.