RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.5 is part of RBSE Solutions for Class 9 Maths. Here we have given Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Ex 8.5.
Board | RBSE |
Class | Class 9 |
Subject | Maths |
Chapter | Chapter 8 |
Chapter Name | Construction of Triangles |
Exercise | Ex 8.5 |
Number of Questions Solved | 3 |
Category | RBSE Solutions |
Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Ex 8.5
Question 1.
Construct a ∆XYZ where ∠XYZ = 60°, XY = 5 cm and XZ = 4.5 cm. How (RBSESolutions.com) many such triangles are possible?
Solution.
Steps of construction:
- Draw a straight line YA.
- With Y as centre, draw an ∠BYA = 60°.
- Taking Y as centre, draw an arc of radius 5 cm which cuts the ray BY at X.
- By taking X as centre, draw an arc of radius 4.5 cm which cuts the base line YA at Z.
- Join XZ.
Hence, required triangle XYZ is obtained.
In this case, only one triangle is possible.
Question 2.
Construct a ∆PQR where ∠PQR = 45°, PQ = 6 cm and PR = 5 cm.
Solution.
Steps of construction:
- Draw PQ = 6 cm as base line.
- At Q, draw an angle of 45° with the (RBSESolutions.com) help of ruler and compass.
- With centre P, take an arc of radius 5 cm which cuts the angle line and mark it as R.
Question 3.
Construct ∆ABC where a = 5.4 cm, b = 6.8 cm and ∠A = 45°. Can two triangles be drawn in this case?
Solution.
Steps of construction:
- Draw a straight line AX.
- Draw an angle of 45° at A i. e., ∠XAY = 45°.
- By taking A as centre, cut an arc of radius 6.8 cm which intersects AY at C.
- Now with centre C, draw an arc of radius 5.4 cm which (RBSESolutions.com) cuts the base line AX at B and B’.
- Join B and B’ to C.
- Hence ∆AB’C and ∆ABC are the required triangles.
Yes, in this case we can draw triangles.
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