# RBSE Solutions for Class 9 Maths Chapter 9 Quadrilaterals Ex 9.4

RBSE Solutions for Class 9 Maths Chapter 9 Quadrilaterals Ex 9.4 is part of RBSE Solutions for Class 9 Maths. Here we have given Rajasthan Board RBSE Class 9 Maths Solutions Chapter 9 Quadrilaterals Ex 9.4.

 Board RBSE Class Class 9 Subject Maths Chapter Chapter 9 Chapter Name Quadrilaterals Exercise Ex 9.4 Number of Questions Solved 6 Category RBSE Solutions

## Rajasthan Board RBSE Class 9 Maths Solutions Chapter 9 Quadrilaterals Ex 9.4

Question 1.
Construct a parallelogram ABCD such (RBSESolutions.com) that AB = 4.7 cm, BC = 3.5 cm and AC = 7 cm.
Solution.
Steps of construction:
1. Draw AB = 4.7 cm.
2. With centre A, draw an arc of radius 3.5 cm and 7 cm respectively.

3. With centre B, draw an arc of 3.5 cm which will intersect the line segment at C.
4. Again by taking C as centre, draw an arc of 4.7 cm which intersects the previous arc at D.
5. Join A to C, A to D, B to C and C to D. Hence, ABCD is required parallelogram.

Question 2.
Construct parallelogram PQRS, when PQ = 5 cm, diagonal PR = 7.6 cm and (RBSESolutions.com) diagonal QS = 5.6 cm.
Solution.
Steps of construction:
1. Draw PQ = 5 cm.
2. With centre P, draw an arc of 3.8 cm and with centre Q draw an arc of 2.8 cm. These arcs intersect at point O (say).
3. Produce PO and QO. With centre P, draw an arc of 7.6 cm and with centre Q draw an arc of 5.6. These arcs cut each other point S and R.

4. Join QR, RS and PS.
Hence, PQRS is the required parallelogram.

Question 3.
Construct a parallelogram ABCD whose two sides are 4.6 cm and 3 cm long (RBSESolutions.com) and included angle is 60°.
Solution.
Steps of construction:
1. Draw AB = 4.6 cm as base line.
2. With centre A, draw an angle of 60°.
3. Take A as centre, draw an arc of 3 cm which cuts, the line segment at D.
4. By taking D and B as centres draw arcs of 4.6 cm and 3 cm which intersect each other at C.

Hence, ABCD is a required parallelogram.

Question 4.
Construct a rectangle ABCD in which AB = 6 cm (RBSESolutions.com) and diagonal AC =10 cm.
Solution.
Steps of construction:
1. Draw a line segment AB = 6 cm.
2. At B draw an angle 90°.
3. With centre A draw an arc of radius 10 cm which cuts the (RBSESolutions.com) previous line segment at C.

4. With centre C draw an arc of 6 cm.
5. Again with A as centre and radius equal to BC, draw arc which cuts previous arc at D.
6. Join BC, CD and AD.
Hence, ABCD is required rectangle.

Question 5.
Construct a rhombus ABCD, such that (RBSESolutions.com) diagonals AC = 7 cm and diagonal BD = 5 cm.
Solution.
Steps of construction:
1. Draw one of the diagonal AC = 7 cm as base.

2. Draw perpendicular bisector of AC which intersects at O.
3. Take O as centre and cut (RBSESolutions.com) an arc of OD = 2.5 cm above and OB = 2.5 cm below the bisector line.
4. Join AD, DC, AB and BC.
Hence, ABCD is the required rhombus.

Question 6.
Construct a square ABCD, the length of whose diagonal is 6 cm.
Solution.
Steps of construction:
1. Draw the diagonal BD of length 6 cm as base.

2. Draw perpendicular (RBSESolutions.com) bisector of DB which intersects DB at O.
3. Take O as centre and draw an arc of 3 cm above and below the line segment BD.
4. Join A, B, C and D.
5. Hence, ABCD is the required square.

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