# RBSE Class 5 Mathematics Model Paper 1 English Medium

RBSE Class 5 Mathematics Model Paper 1 English Medium are part of RBSE Class 5 Mathematics Board Model Papers. Here we have given RBSE Class 5 Mathematics Sample Paper 1 English Medium.

 Board RBSE Textbook SIERT, Rajasthan Class Class 5 Subject Mathematics Paper Set Model Paper 1 Category RBSE Model Papers

## RBSE Class 5 Mathematics Sample Paper 1 English Medium

Time: 2.30 Hours
Maximum Marks: 80

General Instructions to the Students

1. All questions are compulsory.
2. All questions are based on prescribed competencies/leaming area.
3. Weightage of each question is written in front of it.
4. Question paper is divided into 5 parts. Solve all questions.
5. Answer must be written in the space provided below the questions.
6. Do not tear, damage or separate any part of questions paper.

1. Understanding of Shape and Position [8]

Question 1.
Write the name of types of angles formed between the minute hand and hour hand of a clock given below. [2]

Question 2.
Measures the angles with the help of protractor given below. [6]

2. Understanding Number of System [16]

Question 3.
Write the fraction form of shaded part in figure given below: [1]

a. $$\frac{3}{8}$$
b. $$\frac{3}{3}$$
c. $$\frac{3}{6}$$
d. $$\frac{6}{3}$$

Question 4.
Write in digits of two and three upon five [1]
a. $$2 \frac{5}{3}$$
b. $$5 \frac{2}{3}$$
c. $$3 \frac{2}{2}$$
d. $$2 \frac{3}{5}$$

Question 5.
Write the greatest and smallest number of five digits formed from the digits 8, 5, 2, 0, 1. [4]
Smallest number
Greatest number

Question 6.
Write the tick mark of true and false in given box by checking of true and false in given statements. [4]
(1) 48502 in digit form is forty eight thousand five hundred two:
(2) Expanded form of number 1873 is 10,000 + 800 + 70 + 3.
(3) Read the number 40009 four thousand nine.
(4) The place value of 2 in number 73208 is 200.

Question 7.
Write the three equivalent fraction of following fractions: [6]
1. $$\frac{2}{3}$$
2. $$\frac{1}{7}$$

3. Understanding of basic Mathematical Operation [24]

Question 8.
Write the missing digits: [2]

Question 9.
Match the column A or column B [2]

Question 10.
Slove [4]
1. $$\begin{array}{r}{7325} \\ {+1963} \\ \hline\end{array}$$

2. $$\begin{array}{r}{7325} \\ {-6581} \\ \hline\end{array}$$

Question 11.
Find the value of 11 x 16 by sutra Nikhilam as a base 10. [4]

Question 12.
Find the greatest number which divides 15, 45 and 60 completely.[6]

Question 13.
Solve: [6]
(1) There are 165 students in govt, primary school Kheda. A donor gave a 550 Rs per student for school dress.
(2) Mahesh has 345 toffies. He wants equal distribution among 16 friends tell how many toffies will be given to each student and how many remain without distribution? (6)

4. Understanding of Measurement [24]

Question 14.
Identity the True / False statements: [4]
1. Divide by 60 to convert 1 minute into seconds. (True / False)
2. 3600 seconds in one hour (True / False)
3. The time in which minute hand of a clock travels 60 small parts in that time hour hand coverd a distance of big part. (True / False)
4. 1440 minutes in one day. (True/ False)

Question 15.
Fill in the blanks: [4]
1. 1 Kg. =_______ gm.
2. 2500 gm. =_______ Kg.
3. 15 Km. =_______ metre.
4. 100 cm. =_______ metre.

Question 16.
Madhu purchase some items from book store as follows: [4]
1. 8 pencils at the rate of Rs. 4 per pencil.
2. 5 practice books at the rate of Rs. 15 per practice book.
3. 4 pens at the rate of Rs. 10 per pen.
4. 2 Colour box at the rate of Rs. 9 per box.
Find the bill of purchased items in given format that how much rupees spent by Madhu.

Question 17.
Atual has a measurement of 50 ml, 200 ml and 500 ml how he measures the measurement given below such that he used all measures at least once. [6]
1. 2 litre 750 ml.
2. 3 litre 800 ml.

Question 18.
A rectangle is represented in figure. Find the perimeter and area of this rectangel. Do you increase or decrease of length and breadth of it such that perimeter and area will be same if yes then write the measurement of it. [6]

5. Understanding of Data Handling and Pattern [8]

Question 19.
Increase the pattern given below: [1]

 → → ↓

a. ↑
b. ↓
c. ←
d. →

Question 20.
Number 12 is represented by tally marks [1]

Question 21.
Increase the number pattern given below to next two terms [2]
1. 6,10,14,18,_____, _____
2. 35, 29, 23,17, _____, _____

Question 22.
The number of challans who do not follow the traffic rules at cross road by traffic police in Jaipur city are given in tables [4]

 Days Number of challans Monday 5 Tuesday 4 Wednesday 6 Thursday 3

Draw the column chart in given graph of these data.

obtuse angle

1. 90°
2. 60°
3. 115°

c. $$\frac{3}{6}$$

d. $$2 \frac{3}{5}$$

least number = 10258
greatest number = 85210

1. True
2. False
3. False
4. True

1. $$\frac{2}{3}=\frac{4}{6}, \frac{6}{9}, \frac{8}{12}$$
2. $$\frac{1}{7}=\frac{2}{14}, \frac{2}{21}, \frac{4}{28}$$

Hint: nearest base = 10
thus deviation +1 or +6
multiplication of deviation =1 x 6 = 6
in left hand side 11 + 6 = 17
thus product =176

Factor of 15= 1, 3, 5, 15
Factor of 45 = 1, 3, 5, 9, 15, 45
Factor of 60= 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
Equal factor of 15, 45 and 60 = 1, 3, 5, 15
Thus 15 is greatest number.
Which divides 15, 45 and 60 completely

1.

Total number of students =165
amount taken from each student = 550
Total amount = 165 x 550
Thus donor gave the amount = 90750

2. Total toffies = 345

345 Toffies are eually distributed among 16 friends
Then each friend has the toffies
= 345 = 16 = 21
Thus each student will be get 21 toffies and remaining toffies are 9.

1. False
2. True
3. True
4. True

1. 1000
2. 2.5
3. 15000
4. 1

1. 2 liter 750 ml
= 2 × 1000 ml + 750ml
= 2000 ml + 750 ml
= 2750 ml
= 500 ml in five times + 200 ml in one time + 50 in one time
2. 3 liter. 800 ml
= 3 × 1000ml + 800ml
= 3000 ml + 800 ml
= 3800 ml
= 500 ml in 7 times + 200 ml in one time + 100 ml in one time.

Perimeter of rectangle = sum of sides
= 5 + 3 + 5 + 3 = 16 cm
Area of rectangle = length × breadth
= 3 cm × 5 cm = 15 cm²
If the length of rectangle decreased from 5 cm to 4 cm and breadth increased 3 cm to 4 cm then it will be formed a square whose perimeter = 4 × side
4 × 4= 16 cm
Area = (side)² = (4)² = 16 cm²
thus perimeter and area both are same.