RBSE Solutions for Class 6 Maths Chapter 3 Whole Numbers Ex 3.2 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 3 Whole Numbers Exercise 3.2.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 6 |
| Subject | Maths |
| Chapter | Chapter 3 |
| Chapter Name | Whole Numbers |
| Exercise | Ex 3.2 |
| Number of Questions | 10 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 6 Maths Chapter 3 Whole Numbers Ex 3.2
Question 1.
Add the following by (RBSESolutions.com) arranging in proper order.
(i) 85 + 186 + 15
(ii) 175 + 96 + 25
(iii) 65 + 75 + 35
(iv) 55 + 86 + 45
Solution.
Add under associativity –
(i) 85 + 186 + 15
(85 + 186) + 15 = 85 + (186 + 15)
271 + 15 = 85 + 201 ⇒ 286 = 286
(ii) 175 + 96 + 25
(175 + 96) + 25 = 175 + (96 + 25)
271 + 25 = 175 + 121 ⇒ 296 = 296
(iii) 65 + 75 + 35
(65 + 75) + 35 = 65 + (75 + 35)
140 + 35 = 65 + 110 ⇒ 175 = 175
(iv) 55 + 86 + 45
(55 + 86) + 45 = 55 + (86 + 45)
141 + 45 = 55 + 131 ⇒ 186 = 186
Question 2.
Find out the (RBSESolutions.com) multiplication by proper order.
(i) 4 × 1225 × 25
(ii) 4 × 158 × 125
(iii) 4 × 85 × 25
(iv) 8 × 20 × 125
Solution.
Multiply under associativity –
(i) (4 × 1225) × 25 = 1225 × (4 × 25)
4900 × 25 = 1225 × 100 = 122500
(ii) (4 × 158) × 125 = 158 × (4 × 125)
632 × 125 = 158 × 500 = 79000
(iii) (4 × 85) × 25 = 85 × (4 × 25)
340 × 25 = 85 × 100 = 8500
(iv) (8 × 20) × 125 = 20 × (8 × 125)
160 × 125 = 20 × 1000 = 20000
Question 3.
Find out the value of each of the following by (RBSESolutions.com) distributive property.
(i) 185 × 25 + 185 × 75
(ii) 4 × 18 + 4 × 12
(iii) 54279 × 92 + 8 × 54279
(iv) 12 × 8 + 12 × 2
Solution.
Finding each value by distributive law –
(i) 185 × 25 + 185 × 75 = 185 × (26 + 75) – 185 × 100 = 18500
(ii) 4 × 18 + 4 × 12 = 4 × (18 + 12) = 4 × 30 = 120
(iii) 54279 × 92 + 8 × 54279 = 54279 × (92 + 8) = 54279 × 100 = 5427900
(iv) 12 × 8 + 12 × 2 = 12 × (8 + 2) = 12 × 10 = 120
Question 4.
Find out the multiplication by using proper property.
(i) 185 × 106
(ii) 208 × 185
(iii) 54 × 102
(iv) 158 × 1008
Solution.
Solving by (RBSESolutions.com) distribution method of multiplication on addition—
(i) 185 × 106 = 185 × (100 + 6)
= 185 × 100 +185 × 6 = 18500 +1110 = 19610
(ii) 208 × 185 = 185 × 208 = 185 × (200 + 8)
= 185 × 200 + 185 × 8 = 37000 + 1480 = 38480
(iii) 54 × 102 = 54 × (100 + 2)
= 54 × 100 + 54 × 2 = 5400 + 108 = 5508
(iv) 158 × 1008 = 158 × (1000 + 8)
= 158 × 1000 + 158 × 8 = 158000 + 1264 = 159264
Question 5.
Match the following
Solution.
(i) (b)
(ii) (a)
(iii) (d)
(iv) (c)
Question 6.
If the multiplication of any two whole (RBSESolutions.com) numbers is zero, can we say that one or both of the numbers must be zero? Give an example to prove it.
Solution.
Yes, because when zero is multiplied by any number, result is zero
e.g.- 0 × 7 = 0, 8 × 0 = 0, 0 × 0 = 0
Question 7.
If the multiplication of two whole numbers is 1, then can we say that one or both of the numbers are equal to 1? Prove your answer with example.
Solution.
If multiplication of two whole numbers is 1, then definitely one or both the numbers are equal to 1 or should be reciprocal to each other.
eg.- 1 × 1 = 1 and 5 × \(\frac { 1 }{ 5 } \) =1
Question 8.
Find out the following (RBSESolutions.com) by distributive method.
(i) 138 × 101
(ii) 125 × 400
(iii) 608 × 35
Solution.
Solving by distribution method of multiplication on addition –
(i) 138 × 101 = 138 × (100 + 1)
= 138 × 100 + 138 × 1 = 13800 + 138 = 13938
(ii) 125 × 400 = 125 × (300 + 100)
= 125 × 300 + 125 × 100 = 37500 + 12500 = 50000
(iii) 608 × 35 = 608 × (30 + 5)
= 608 × 30 + 608 × 5 = 18240 + 3040 = 21280
Question 9.
Which of the following will not result in zero ?
(i) 1 + 0
(ii) 0 × 0
(iii) \(\frac { 0 }{ 2 } \)
(iv) 10 – \(\frac { 10 }{ 2 } \)
Solution.
Solving each
(i) 1 + 0 = 1 will not result in zero
(ii) 0 × 0 = 0 will result in zero
(iii) \(\frac { 0 }{ 2 } \) = 0 will result in zero
(iv) 10 – \(\frac { 10 }{ 2 } \) = 10 – 5 = 5 will not result in zero
Question 10.
Choose a, b, c…. and write (RBSESolutions.com) in the bracket.
(i) Which of the following has the commutative property of addition?
(a) 5 × 8 = 8 × 5
(b) (2 × 3) × 5 = 2 × (3 × 5)
(c) (12 + 8) + 10 = (2 + 8) + 10
(d) 15 + 8 = 8 + 15
(ii) Which of the following has commutative property of multiplication.
(a) 10 × 20 = 20 × 10
(b) 10 × 10 = 20 × 20
(c) (10 × 20) = 10 × 1
(d) 10 + 20 = 10 × 20
Solution.
(i) (d)
(ii) (a).
We hope the RBSE Solutions for Class 6 Maths Chapter 3 Whole Numbers Ex 3.2 will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 3 Whole Numbers Exercise 3.2, drop a comment below and we will get back to you at the earliest.