RBSE Solutions for Class 10 Maths Chapter 17 Measures of Central Tendency Ex 17.3 is part of RBSE Solutions for Class 10 Maths. Here we have given Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Exercise 17.3.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 10 |
| Subject | Maths |
| Chapter | Chapter 17 |
| Chapter Name | Measures of Central Tendency |
| Exercise | Exercise 17.3 |
| Number of Questions Solved | 6 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Ex 17.3
Find the mean (arithmetic) of following (RBSESolutions.com) frequency distribution (Q. 1 – 4)
Ex 17.3 Class 10 RBSE Question 1.
Solution :
Calculation of arithmetic mean
Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 1580 }{ 60 } \) = 26.33(approx)
RBSE Solutions For Class 10 Maths Chapter 17.3 Question 2.
Solution :
Calculation of arithmetic (RBSESolutions.com) mean
Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 618 }{ 40 } \) = 15.45
Exercise 17.3 Class 10 RBSE Question 3.
Solution:
Calculation of arithmetic mean :
Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 10200 }{ 70 } \) = 145.71
Thus, required (RBSESolutions.com) arithmetic mean = 145.71
RBSE Solutions For Class 10 Maths Chapter 17 Question 4.
Solution:
Calculation of arithmetic mean :
Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 1980 }{ 40 } \) = 49.5
Thus, required arithmetic mean = 49.5
RBSE Solution Class 10 Maths Chapter 17 Question 5.
Find mean of the following (RBSESolutions.com) frequency distribution :
Solution:
Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 6820 }{ 100 } \) = 68.2
Thus, frequency distribution mean = 68.2
Class 10 Maths RBSE Solution Chapter 17 Question 6.
The salary of employees in a factory are (RBSESolutions.com) according to following table :
Find the arithmetic mean of salary.
Solution :
Calculation of arithmetic mean :
Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 102000 }{ 70 } \) = 1457.14
Thus, arithmetic (RBSESolutions.com) mean of salary = ₹ 1457.14
We hope the given RBSE Solutions for Class 10 Maths Chapter 17 Measures of Central Tendency Ex 17.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Exercise 17.3, drop a comment below and we will get back to you at the earliest.