RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics Additional Questions is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 6 Vedic Mathematics Additional Questions.
| Board | RBSE | 
| Textbook | SIERT, Rajasthan | 
| Class | Class 7 | 
| Subject | Maths | 
| Chapter | Chapter 6 | 
| Chapter Name | Vedic Mathematics | 
| Exercise | Additional Questions | 
| Number of Questions | 8 | 
| Category | RBSE Solutions | 
Rajasthan Board RBSE Class 7 Maths Chapter 6 Vedic Mathematics Additional Questions
Multiple Choice Questions
Question 1
 The sum of 27 + 58 + 392 + 68 + 32 + 23 will be :
 (a) 600
 (b) 500
 (c) 400
 (d) 300
Question 2
 The number is find on (RBSESolutions.com) subtracting 569 from 854 is :
 (a) 285
 (b) 284
 (c) 208
 (d) 289
 Answer:
 1. (a).
 2. (a).
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Fill in the blanks :
 (i) Product of fractions 5\(\frac { 1 }{ 2 }\) x 6 will be
 (ii) Value of 6\(\frac { 1 }{ 4 }\) x 6\(\frac { 3 }{ 4 }\) is
 (iii) Value of 3\(\frac { 3 }{ 4 }\) – 3\(\frac { 2 }{ 5 }\) is
 Answer:
 (i) 33
 (ii) 42\(\frac { 3 }{ 16 }\)
 (iii) \(\frac { 7 }{ 20 }\)
Short Answer Type Questions
Question 1
 Find the (RBSESolutions.com) sum of
 45 + 67 + 38 + 55 + 62 + 33
 Solution:
 (45 + 55) + (67 + 33) + (38 + 62) = 100 + 100 + 100 = 300
Question 2
 Multiply 81 with 11.
 Solution:
 
Question 3
 Find the greater fractions (RBSESolutions.com) in \(\frac { 3 }{ 4 }\) व \(\frac { 4 }{ 5 }\)
 Solution:
 (i) Write numerator and denominator of fractions
 (ii) 3 x 5 = 15 and 4 x 4 = 15
 \(\frac { 3 }{ 4 }\) < \(\frac { 4 }{ 5 }\)
Question 4
 Solve:
 3\(\frac { 3 }{ 4 }\)  – 3\(\frac { 2 }{ 5 }\)
 Solution:
 
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Question 5
 Multiply :
 7\(\frac { 1 }{ 2 }\) and 8\(\frac { 1 }{ 2 }\)
 Solution:
 
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