# RBSE Solutions for Class 8 Maths Chapter 3 Powers and Exponents Ex 3.1

RBSE Solutions for Class 8 Maths Chapter 3 Powers and Exponents Ex 3.1 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 3 Powers and Exponents Exercise 3.1.

 Board RBSE Textbook SIERT, Rajasthan Class Class 8 Subject Maths Chapter Chapter 3 Chapter Name Powers and Exponents Exercise Exercise 3.1 Number of Questions 10 Category RBSE Solutions

## Rajasthan Board RBSE Class 8 Maths Chapter 3 Powers and Exponents Ex 3.1

Question 1.
Simplify the following

Solution.

Question 2.
Find the values

Solution.
(i) (-5)3
= (-1 × 5)3
= (-1)3 × (5)3
= (-1) × 5 × 5 × 5
= – 125

Question 3.
With the help of Prime factor, change the following into exponent form

Solution.

Question 4.
Find the values

Solution.
(i) 32 × 33
32+3 = 35 = 3 × 3 × 3 × 3 × 3
= 243

Question 5.

Solution.
(i) 45 ÷ 42
= 45 ÷ 42
= 452
= 43
(ii) (- 5)7 ÷ (- 5)4
= (- 5)7-4
=(- 5)3

Question 6.
Find the value
(i) (32)3
(ii) (23)2
(iii) (52)2
(iv) (-24)2

Solution.
(i) (32)3
= (3 x 3)3
=93
= 9 x 9 x 9 = 729
(ii) (23)2
= 23 x 2
= 26
= 2 x 2 x 2 x 2 x 2 x 2=64
(iii) (52)2
= 52×2
= 54
= 5 x 5 x 5 x 5 = 625
(iv) (- 24)2
= (- 2 x 2 x 2 x 2)2
= (- 16)2
= {(- 1) x 16)2
= (- 1)2 x (16)2
= 1 x 16 x 16 = 256

Question 7.
Find the value
(i) 30
(ii) 75-5
(iii) (-2)3-3
(iv) $${ \left( \frac { 2 }{ 3 } \right) }^{ 2+3-5 }$$
(v) 20 × 30
(vi) 20 + 50
(vii) $${ \left( \frac { 7 }{ 15 } \right) }^{ 0 }+{ \left( \frac { 1 }{ 7 } \right) }^{ 3-3 }$$
Solution.
(i) 30
30 = 1
(ii) 75-5
75-5 = 7= 1
(iii) (- 2)3-3
(- 2)3-3 = (- 2)0 = 1
(iv) $${ \left( \frac { 2 }{ 3 } \right) }^{ 2+3-5 }$$
$${ \left( \frac { 2 }{ 5 } \right) }^{ 2+3-5 }$$
$${ \left( \frac { 2 }{ 5 } \right) }^{ 0 }=1$$
(v) 20 X 30
20 x 30 = 1 x 1 = 1
(vi)2+ 50
20 + 50 = 1 + 1 = 2

Question 8.
Change into positive exponent numbers
(i) 2-3
(ii) 3-5
(iii) a-4
(iv) (-2)-5
(v) (-x)-3
(vi) $$\frac { 1 }{ { 5 }^{ -3 } }$$
(vii) $$\frac { 1 }{ { y }^{ -3 } }$$
(viii) $$\frac { 1 }{ { \left( \frac { 2 }{ 3 } \right) }^{ -3 } }$$
Solution.
(i) 2-3

Question 9.
Simplify the following ¡n form of exponent

Solution.
(i) (22 x 33)2
= (2 x 2 x 3 x 3 x 3)2
= (108)2
= 108 X 108
= 11664

Question 10.
Find the values of

Solution.

= (3)² + (2)² + (4)²
=9 + 4 + 16
= 29

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