RBSE Solutions for Class 5 Maths Chapter 17 Mental Mathematics Ex 17.2 is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 17 Mental Mathematics Exercise 17.2.
| Board | RBSE |
| Textbook | SIERT, Rajasthan |
| Class | Class 5 |
| Subject | Maths |
| Chapter | Chapter 17 |
| Chapter Name | Mental Mathematics |
| Exercise | Ex 17.2 |
| Number of Questions | 11 |
| Category | RBSE Solutions |
Rajasthan Board RBSE Class 5 Maths Chapter 17 Mental Mathematics Ex 17.2
Question 1.
Choose the correct option in the following


Solution.
(i) (c)
(ii) (a)
(iii) (c)
(iv) (b)
(v) (c)
(vi) (b)
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Question 2.
25 should be multiplied with which one digit(RBSESolutions.com)number to get a number having 0 at the tens and units place.
Solution.
If 25 is multiplied with 4 or 8 (one of them) then we get 0 at the tens and units place.
that is 25 x 4 = 100
and 25 x 8 = 200.
Question 3.
To obtain ten times of a given number with which number it should be multiplied.
Solution.
To obtain 10 times of a given(RBSESolutions.com)number it should be multiplied by 10.
Question 4.
Which number when multiplied by 5 gives products having 5 at the units place?
Solution.
Total 5 digits (1, 3, 5, 7, 9)
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Question 5.
To find half of a number, by which number it should be divided.
Solution.
To find half of a number, the number should be divided by 2.
Question 6.
Find out a 2 – digits number whose(RBSESolutions.com)both digits are same and the number is divided by 7.
Solution.
Number is 77.
Question 7.
Find out a number, which divides all numbers.
Solution.
This number is 1 which divides all the numbers.
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Question 8.
What operation we have to apply on 9 and 6, so that we have 54 as the number.
Solution.
To obtain 54, only multiplication performed between 9 and 6.
Question 9.
What operation we have to(RBSESolutions.com)apply on 6 and 3, so that we have 2 as answer.
Solution.
Only division operation is applied to obtain 2 from 6 and 3.
Question 10.
Which number when multiplied by any number gives the answer zero ?
Solution.
‘0’ is the only number which when multiplied by any number gives zero as answer.
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Question 11.
Find out the smallest(RBSESolutions.com)number of 2 digits which is divisible by 2 and 3.
Solution.
Smallest 2 digit number is 12 which is divisible by 2 and 3 both.
We hope the RBSE Solutions for Class 5 Maths Chapter 17 Mental Mathematics Ex 17.2 will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 17 Mental Mathematics Exercise 17.2, drop a comment below and we will get back to you at the earliest.