RBSE Solutions for Class 6 Maths Chapter 13 Ratio and Proportion Ex 13.3 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 13 Ratio and Proportion Exercise 13.3.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 13 |

Chapter Name |
Ratio and Proportion |

Exercise |
Ex 13.3 |

Number of Questions |
11 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 6 Maths Chapter 13 Ratio and Proportion Ex 13.3

Question 1.

If the cost of 1 quintal of sugar is Rs 2700, find (RBSESolutions.com) the cost of 1 kg sugar.

Solution:

Cost of 1 quintal of sugar = Rs. 2700

or cost of 100 kg of sugar= Rs. 2700

⇒ Cost of 1 kg of sugar = \(\frac { 2700 }{ 100 } \) = Rs. 27

Thus, cost of 1 kg of sugar is Rs 27.

Question 2.

The bus fare for 200 km is Rs 150. What (RBSESolutions.com) will be the fare for 500 km?

Solution:

Bus fare of for 200 km = Rs. 150

⇒ Bus fare for 1 km = Rs. \(\frac { 150 }{ 200 } \)

∴ Bus fare for 500 km

= \(\frac { 150\times 500 }{ 200 } \) = Rs 375.

Thus, Rs. 375 will be the fare for 500 km.

Question 3.

If the interest on Rs. 700 is Rs. 168 for a (RBSESolutions.com) certain amount of time. What will be the interest on Rs. 1500 for the same time and same rate of interest?

Solution:

Interest for Rs. 700 = Rs. 168

⇒ Interest for Rs. 1 = Rs. \(\frac { 168 }{ 700 } \)

⇒ Interest for Rs 1500 = Rs. \(\frac { 168\times 1500 }{ 700 } \)

= Rs. 360

Thus, Rs 360 will be the interest on Rs. 1500 for the same time and some rate of interest.

Question 4.

In a day, 6 girls were able to fence 18 plants. Then 15 girls can (RBSESolutions.com) fence how many plants in a day?

Solution:

6 girls fence= 18 plants

⇒ 1 girls can fence = \(\frac { 18 }{ 6 } \) plants

⇒ 15 girls can fence = \(\frac { 18\times 15 }{ 6 } \) plants

= 45 plants

Thus, 15 girls can fence 45 plants in a day.

Question 5.

5 persons can save 15 litres of water if they take bath using (RBSESolutions.com) a bucket instead of shower. Then 25 persons can save how many litres of water?

Solution:

5 person can save = 15l of water

⇒ 1 person can save = \(\frac { 15 }{ 5 } \) litres of water

⇒ 25 person can save

\(=\frac { 15\times 25 }{ 5 } \) litres of water = 75 litres of water

5 Thus, 25 persons can save 75l of water.

Question 6.

A motorbike travels 120 km in 2 litres of petrol. How (RBSESolutions.com) many litres of petrol will it require to travel 300 km?

Solution:

Petrol requires for travelling 120 km = 2l

⇒ Petrol requires for travelling 1 km

\(=\frac { 2 }{ 120 } \) litres

⇒ Petrol requires for travelling 300 km

\(=\frac { 2\times 300 }{ 120 } \) litres= 5 litres

Thus, 5l of petrol will be requires to travel 300 km.

Question 7.

A train travels 130 km in 2 hours. How much (RBSESolutions.com) time it required to cover 520 km with the same speed?

Solution:

Time requires in travelling 130 km = 2 hours

⇒ Time requires in travelling 1 km = \(\frac { 2 }{ 130 } \) hours

⇒ Time requires in travelling 520 km

\(=\frac { 2\times 520 }{ 130 } \) hours = 8 hours

Thus, 8 hours required to cover 520 km with the same speed.

Question 8.

Cost of 4 chairs is Rs. 900. How many such (RBSESolutions.com) chairs can be purchased for Rs. 33750?

Solution:

Rs. 900 is cost of = 4 chairs

⇒ Rs. 1 is cost of = \(\frac { 4 }{ 900 } \) chairs

⇒ Rs. 33750 is cost of = \(\frac { 4\times 33750 }{ 900 } \) chairs

= 150 chairs

Thus, 150 chairs can be purchased for Rs. 33750.

Question 9.

Geeta pays Rs. 10500 as rent for 3 months. How much does (RBSESolutions.com) she has to pay for a whole year, (if the rent per month remains same)?

Solution:

Rent for 3 months= Rs. 10500

Geeta has to pay Rs 42000, for a whole year.

Question 10.

Rahim made 48 runs in 8 overs and Kabir made. 54 runs in 6 overs. Who (RBSESolutions.com) made more runs per over?

Solution:

Rahim made in 8 overs = 48 Runs

or Rahim made in 1 over = \(\frac { 48 }{ 8 } \) = 6 Runs

Similarly, Kabir made in 6 overs = 54 Runs

or Kabir made in 1 over = \(\frac { 54 }{ 6 } \) = 9 Runs

Thus, Kabir mad more runs per over.

Question 11.

Cost of 3 kg of (RBSESolutions.com) millet is Rs. 49.50.

(i) What will be the cost of 7 kg of millet?

(ii) What quantity of millet can be purchased in Rs 165?

Solution:

(i) Cost of 3 kg millet = Rs. 49.50

= 115.50 Rupees

Thus, Rs. 115.50 will be the cost of 7 kg of millet.

(ii) Millet purchased (RBSESolutions.com) in Rs. 49.50 = 3 kg

10 kg of millet can be purchased in Rs. 165.

We hope the RBSE Solutions for Class 6 Maths Chapter 13 Ratio and Proportion Ex 13.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 13 Ratio and Proportion Exercise 13.3, drop a comment below and we will get back to you at the earliest.