A sequence is given by the recursive rule t1 = 2, tn+1 = 3tn-2 for n ≥ 1. Which term of the sequence Class 9

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· Jul 10, 2026 · Reviewed & updated Sep 17, 2026 · 1 min read

A sequence is given by the recursive rule t1 = 2, tn+1 = 3tn-2 for n ≥ 1. Which term of the sequence Class 9

Question 1.

A sequence is given by the recursive rule t1 = 2, tn+1 = 3tn-2 for n ≥ 1. Which term of the sequence is 730? Class 9

Solution:

Here, t1 = 2, tn+1 = 3n-2 for n ≥ 1

Finding the few terms

t2 = 3(2) -2 = 4

t3 = 3(4) - 2 = 10

t4 = 3(10) - 2 = 28

t5 = 3(28) - 2 = 82

t6 = 3(82) - 2 = 244

t7 = 3(244) - 2 = 730

∴ 730 is the 7th term of the sequence.


Question 2.

Which term of the GP: 2, 6, 18,... is 4374? Write the explicit formula as well as the recursive formula for the nth term. Class 9

Solution:

Here, a = 2, r = $\frac{6}{2}$ = 3

tn = arn-1

∴ tn = 2 × 3n-1

∴ tn = 2 × 3n-1 is the explicit formula for the nn-1 term.

Suppose nth term is 4374

∴ tn = 4374

∴ 2 × 3n-1 = 4374

∴ 3n-1 = $\frac{4374}{2}$ = 2187

∴ 3n-1 = 37

∴ n - 1 = 7

∴ n = 8

∴ 4374 is the 8th term of the GP.

Recursive formula is

t1 = 2, tn = 3 × tn-1 for n ≥ 2