Maths ·Class 6 Maths

Carry out the following subtractions using Brahmagupta’s method : Class 6

RBSEGuide

· Jun 30, 2026 · Reviewed & updated Sep 17, 2026 · 1 min read

Question 1.

Solution:

(a) $\frac{8}{15}-\frac{3}{15}=\frac{5}{15}=\frac{1}{3}$.

(b) $\frac{2}{5}-\frac{4}{15}=\frac{2 \times 3}{5 \times 3}-\frac{4}{15}=\frac{6}{15}-\frac{4}{15}=\frac{2}{15}$.

(c) $\frac{5}{6}-\frac{4}{9}=\frac{5 \times 3}{6 \times 3}-\frac{4 \times 2}{9 \times 2}=\frac{15}{18}-\frac{8}{18}=\frac{7}{18}$.

(d) $\frac{2}{3}-\frac{1}{2}=\frac{2 \times 2}{3 \times 2}-\frac{1 \times 3}{2 \times 3}=\frac{4}{6}-\frac{3}{6}=\frac{1}{6}$.

Question 2.

Subtract as indicated : Class 6

Solution:

(a) $\frac{10}{3}-\frac{13}{4}=\frac{10 \times 4}{3 \times 4}-\frac{13 \times 3}{4 \times 3}$

$=\frac{40}{12}-\frac{39}{12}=\frac{1}{12}$.

(b) $\frac{23}{3}-\frac{18}{5}=\frac{23 \times 5}{3 \times 5}-\frac{18 \times 3}{5 \times 3}$

$=\frac{115}{15}-\frac{54}{15}=\frac{61}{15}=4 \frac{1}{15}$.