Draw the graphs of the following sets of lines. In each case, reflect on the role of 'a' and 'b'. Class 9
Draw the graphs of the following sets of lines. In each case, reflect on the role of 'a' and 'b'. Class 9
Question 1.
Draw the graphs of the following sets of lines. In each case, reflect on the role of 'a' and 'b'. Class 9
i. y = 4x, y = 2x, y = x
ii. y = -6x, y = -3x, y = -x
iii. y = 5x, y = -5x
iv. y = 3x - 1, y = 3x, y = 3x + 1
v. y = 2x - 3, y = -2x, y = 2x + 3.
Solution:
i. For y = 4x,
| x | 0 | 1 |
| y | 0 | 4 |
For y = 2x,
| x | 0 | 1 |
| y | 0 | 2 |
For y = x,
| x | 0 | 1 |
| y | 0 | 1 |

Since b = 0 for all three lines
∴ All lines pass through the origin and none of the lines shifts up or down.
As a increases from 1 to 4, the line becomes steeper.
Since a > 0 for all three lines
∴ All three lines represent linear growth.
ii. For y = -6x
| x | 0 | -1 |
| y | 0 | 6 |
For y = -3x
| x | 0 | -1 |
| y | 0 | 3 |
For y = -x
| x | 0 | -4 |
| y | 0 | 4 |

Since b = 0 for all three lines
∴ All lines pass through the origin and none of the lines shifts up or down.
As a increases from -6 to -1, the line becomes less steep
since a < 0 for all three lines
∴ All three lines represent linear decay.
iii. For y = 5x
| x | 0 | 1 |
| y | 0 | 5 |
For y = -5x
| x | 0 | -1 |
| y | 0 | 5 |

Since b = 0 for both lines y = -5x and y = 5x
∴ Both lines passes through origin
For y = -5x, a < 0
∴ y = -5x represents linear decay,
For y = 5x, a > 0
∴ y = 5x represents linear growth,
iv. For y = 3x - 1
| x | 0 | 1 |
| y | -1 | 2 |
For y = 3x
| x | 0 | 2 |
| y | 0 | 6 |
For y = 3x + 1
| x | 0 | 1 |
| y | 1 | 4 |

Since a = 3 for all the three lines
∴ The lines are parallel.
For y = 3x, b = 0
∴ It passes through the origin
For the lines y = 3x + 1 and y = 3x - 1, the y-intercepts are 1 and - 1 respectively.
i.e., the lines cut the y-axis at (1, 0) and (-1, 0) respectively.
v. For y = -2x - 3
| x | 0 | 1 |
| y | -3 | -5 |
For y = -2x
| x | 0 | 1 |
| y | 0 | -2 |
For y = 2x + 3
| x | 0 | 1 |
| y | 3 | 5 |

Since a = -2 for y = -2x - 3 and y = -2x,
∴ The two lines are parallel
Since a < 0, the two lines represent linear decay
Since a > 0 for y = 2x + 3, the line represents linear growth
Since b = 0 for y = 2x
∴ It passes through origin
For y = -2x - 3 and y = 2x + 3, the y-intercept are -3 and 3 respectively, i.e., the lines cuts y-axis at (0, -3) and (0, 3) respectively.