Find the first five terms of the sequence in which the nth term is given by Class 9
Find the first five terms of the sequence in which the nth term is given by Class 9
Question 1.
Find the first five terms of the sequence in which the nth term is given by Class 9
i. tn = 3n - 4,
ii. tn = 2 - 5n, and
iii. tn = n² - 2n + 3 for n > 1.
Solution:
i. For tn = 3n - 4,
t1 = 3(1) - 4 = 3 - 4 = -1
t2 = 3(2) - 4 = 6 - 4 = 2
t3 = 3(3) - 4 = 9 - 4 = 5
t4 = 3(4) - 4 = 12 - 4 = 8
t5 = 3(5) - 4 = 15 - 4 = 11
∴ First five terms are -1, 2, 5, 8, 11.
ii. For tn = 2 - 5n,
t1 = 2 - 5(1) = 2 - 5 = -3
t2 = 2 - 5(2) = 2 - 10 = -8
t3 = 2 - 5(3) = 2 - 15 = -13
t4 = 2 - 5(4) = 2 - 20 = -18
t5 = 2 - 5(5) = 2 - 25 = -23
∴ First five terms are -3, -8, -13, -18, -23.
iii. For tn = n² - 2n + 3,
t1 = (1)² - 2(1) + 3 = 1 - 2 + 3 = 2
t2 = (2)² - 2(2) + 3 = 4 - 4 + 3 = 3
t3 = (3)² - 2(3) + 3 = 9 - 6 + 3 = 6
t4 = (4)² - 2(4) + 3 = 16 - 8 + 3 = 11
t5 = (5)² - 2(5) + 3 = 25 - 10 + 3 = 18
∴ First five terms are 2, 3, 6, 11, 18.