The following table shows the coordinates of points S, M and T. In each case, state whether M Class 9
The following table shows the coordinates of points S, M and T. In each case, state whether M Class 9
Question 1.
The following table shows the ! coordinates of points S, M and T. In each case, state whether M is the midpoint ; of segment ST. Justify your answer. Class 9

When M is the mid-point of ST, can you ! find any connection between the coordinates of M, S and T?
Solution:
When M is the midpoint of ST, then SM = MT
i. SM = $\sqrt{(-3-0)^2+(0-0)^2}$ = 3 units
MT = $\sqrt{(3-0)^2+(0-0)^2}$ = 3 units
∴ SM = MT
∴ M is the midpoint of ST
ii. SM = $\sqrt{(3-2)^2+(4-3)^2}$ = $\sqrt{2}$ units
MT = $\sqrt{(4-3)^2+(5-4)^2}$ = $\sqrt{2}$ units
∴ SM = MT
∴ M is the midpoint of ST
iii. SM = $=\sqrt{(0-0)^2+(5-0)^2}$ = 5 units
MT = $\sqrt{(0-0)^2+(5+10)^2}$ = 15 units
∴ SM ≠ MT
∴ M is not the midpoint of ST
iv. SM = $\sqrt{(0+8)^2+(-2-7)^2}$ = $\sqrt{145}$ units
MT = $\sqrt{(6-0)^2+(-3+2)^2}$ = $\sqrt{37}$ units
∴ SM ≠ MT
∴ M is not the midpoint of ST
Now, 3 = $3=\frac{4+2}{2}$ and $4=\frac{5+3}{2}$
We observe that coordinates of midpoint are the average of coordinates of the two endpoints.
| S | M | T | Is M the midpoint of ST? Yes or No | Reason for your answer | |
| i. | (-3, 0) | (0, 0) | (3, 0) | Yes | SM = MT |
| ii. | (2, 3) | (3, 4) | (4, 5) | Yes | SM = MT |
| iii. | (0, 0) | (0, 5) | (0, -10) | No | SM ≠ MT |
| iv. | (-8, 7) | (0, -2) | (6, -3) | No | SM ≠ MT |