The wheel of a car has an outer radius of 28 cm. Calculate how far the car travels after one complete Class 9

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· Jul 15, 2026 · Reviewed & updated Sep 17, 2026 · 1 min read

The wheel of a car has an outer radius of 28 cm. Calculate how far the car travels after one complete Class 9

Question 1.

The wheel of a car has an outer radius of 28 cm. Calculate how far the car travels after one complete turn of the wheel, and how many times the wheel turns during a journey of 1 km. Class 9

Solution:

Given:

Outer radius of wheel (r) = 28 cm

Distance travelled by wheel in one complete turn = Circumference of circle = 2πr

= 2 × $\frac{22}{7}$ × 28

= 44 × 4 = 176 cm

∴ Distance travelled by car in one turn = 176 cm

Now, car travelled a distance of 1 km.

∴ 1km = 100000 cm

Number of turns

$=\frac{\text { Total distance travelled }}{\text { Distance travelled in one turn }}=\frac{100000}{176}=568.18$

∴ Number of turns ≈ 568


Question 2.

Two rectangles have the same area and the same perimeter. Does this mean that they are congruent to each other? Class 9

Solution:

Let the two rectangles have dimensions

(l1, b1) and (l2, b2).

Both triangles have same perimeter

l1 + b1 = l2 + b2 ...(i)

Also, they have same area

l1 · b1 = l2 · b2 ... (ii)

From (i) and (ii)

l1, b1 and l2, b2 are roots of the same quadratic equation

x - (l1 + b1)x + l1b1 = 0

So {l1, b1} = {l2, b2} as sets.

Hence either l1 = l2 and b1 = b2, OR l1 = b2 and b1 = l2.

In both cases, the rectangles are congruent (a rectangle and its 90°-rotation are congruent).

Yes - two rectangles with the same area and the same perimeter must be congruent.