Using the formula tn = a + (n -1) × d, find the nth term of the following arithmetic progressions. Class 9
R
RBSEGuide
Using the formula tn = a + (n -1) × d, find the nth term of the following arithmetic progressions. Class 9
Question 1.
Using the formula tn = a + (n -1) × d, find the nth term of the following arithmetic progressions. Class 9
i. $\frac{1}{2}, \frac{5}{2}, \frac{9}{2}, \frac{13}{2}$
ii. 1.5, 3.5, 5.5, 7.5,...
Answer:
i. Given AP is $\frac{1}{2}, \frac{5}{2}, \frac{9}{2}, \frac{13}{2}$.
Here, a = $\frac{1}{2}$ and d = $\frac{5}{2}-\frac{1}{2}=\frac{4}{2}=2$
∴ tn = a + (n - 1)d
∴ tn = $\frac{1}{2}$ + (n - 1) × 2
∴ tn = $\frac{1}{2}$ + 2n - 2
∴ tn = 2n - $\frac{3}{2}$
∴ tn = $\frac{4 n-3}{2}$
ii. Given AP is 1.5, 3.5, 5.5, 7.5
Here, a = 1.5 and d = 3.5 - 1.5 = 2
∴ tn = a + (n - 1)d
∴ tn = 1.5 + (n - 1) × 2
∴ tn = 1.5 + 2n - 2
∴ tn = 2n - 0.5