We already know that x² - y² = (x - y) (x + y). Further, we have verified that x^3 - y^3 = (x - y) (x² + xy + y²). Class 9

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· Jul 07, 2026 · Reviewed & updated Sep 17, 2026 · 1 min read

We already know that x² - y² = (x - y) (x + y). Further, we have verified that x^3 - y^3 = (x - y) (x² + xy + y²). Class 9

Question 1.

We already know that x² - y² = (x - y) (x + y). Further, we have verified that x3 - y3 = (x - y) (x² + xy + y²). Observe that x - y is a common factor of x² - y² and x3 - y3. Do you think x - y is also a factor of x4 - y4 ? Note that x4 - y4 = (x)² - (y)² = (x² + y²). Can you see how x - y is a factor of x4 - y4? How about x5 - y5? Does this also have x - y as a factor? Class 9

Answer:

x4 - y4 = (x²)² - (y²)²

= (x² - y²) (x² + y²)

= (x - y) (x + y) (x² + y²)

Thus, x - y is also a factor of x4 - y4.

x5 - y5 = (x - y) (x4 + x3y + x²y² + xy3 + y4)

Thus, x - y is also a factor of x5 - y5.

[Note: In general, x - y is a factor of xn - yn where n is a natural number.]