# RBSE Solutions for Class 6 Maths Chapter 4 Negative Numbers and Integers Ex 4.3

RBSE Solutions for Class 6 Maths Chapter 4 Negative Numbers and Integers Ex 4.3 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 4 Negative Numbers and Integers Exercise 4.3.

 Board RBSE Textbook SIERT, Rajasthan Class Class 6 Subject Maths Chapter Chapter 4 Chapter Name Negative Numbers and Integers Exercise Ex 4.3 Number of Questions 4 Category RBSE Solutions

## Rajasthan Board RBSE Class 6 Maths Chapter 4 Negative Numbers and Integers Ex 4.3

Question 1.
Subtract the (RBSESolutions.com) following.
(i) + 32 – (+12)
(ii) + 7 – (+15)
(iii) (-14) – (-20)
(iv) (-30) – (-15)
(v) 23 – (-10)
(vi) (-27) – 22
Solution.
(i) + 32 – (+12) = 32 – 12 = 20
(ii) + 7 – (+15) = 7 – 15 = – 8
(iii) (-14) – (-20) = – 14 + 20 = 20 – 14 = 6
(iv) (-30) – (-15) = – 30 + 15 = 15 – 30 = – 15
(v) 23 – (-10) = 23 + 10 = 33
(vi) (-27) – 22 = – 27 – 22 = – 49

Question 2.
Fill in the (RBSESolutions.com) blanks.
(i) – 5 + ………………… = 0
(ii) 7 + ………………… = 0
(iii) 11 + (-11) = …………………
(iv) (- 3) + ………………… = – 7
(v) 14 – ………………… = 16
(vi) (- 4) + ………………… = – 8
Solution.
(i) -5 + 5 = 0
(ii) 7 + (-7) = 0
(iii) 11 + (-11) = 0
(iv) (-3) + (-4) = – 7
(v) 14 – (- 2) = 16
(vi) (-4) +(-4) = – 8

Question 3.
Fill in the blanks (RBSESolutions.com) with the sign > , < or =
(i) (-2) + (-9) …………….. (-2) + (-4)
(-21) + (-10) …………….. (-10) + (-21)
(iii) 45 – (-12) …………….. (-12) + 45
(iv) (- 14) + (14) …………….. (-7) + (1)
Solution.
Filling the blanks with sign
(i)( -2) + (-9) = -2 -9 = – 11
and (-2) + (-4) = -2 -4 = – 6
∴(-2) + (-9) < (-2) + (-4)

(ii) (- 21) + (- 10) ……….. (- 10) + (- 21)
(-21) + (-10) = – 21 – 10 = – 31
and (-10) + (-21) = -10 -21 = -31
∴ (-21) + (-10) = (-10) + (-21)

(iii)45- (-12) (- 12) + 45
45 – (-12) = 45 + 12 = 57
and (-12) + 45 = -12 + 45 = 33
∴ 45- (-12) > (-12) + 45

(iv) (-14) + (14) ……………….. (-7) + (1)
(-14) + (14) = -14 + 14 = 0
and (-7) + (1) = 7 + 1 = -6
∴ (-14) + (14) > (-7) + (1)

Question 4.
Find the value (RBSESolutions.com) of the following.
(i) (-7) + (-4) + 11
(ii) (-12) + (-3) – (-4)
(iii) 14 – 8 – (-2)
(iv) (- 24) + (-12) – (-8)
Solution.
(i) (-7) + (-4) + 11
= -7 -4 +11 = -11 + 11 = 0
(ii) (-12) + (-3) – (-4)
= -12 -3 + 4 = -15 + 4 = -11
(iii) 14 – 8 – (-2) = 14 – 8 + 2
= 14 + 2- 8= 16 – 8 = 8
(iv) (-24) + (-12) – (-8)
= -24 -12 + 8 = -36 + 8 = -28

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