RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.4

RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.4 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 7 Construction of Quadrilaterals Exercise 7.4.

 Board RBSE Textbook SIERT, Rajasthan Class Class 8 Subject Maths Chapter Chapter 7 Chapter Name Construction of Quadrilaterals Exercise Exercise 7.4 Number of Questions 5 Category RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.4

Question 1.
Construct a quadrilateral KLMN, in which KL = 4.8 cm., LM = 5.0 cm., MN = 3.8 cm., ∠L = 72°, ∠M = 105°.
Solution
First of all we draw a(RBSESolutions.com)rough sketch of the given measurements :

Steps of Construction

1. First of all, draw a line segment KL = 4.8 cm.
2. At point, L construct ∠KLX = 72°. We cut an arc of 5.0 cm on LX from point L. Mark the point as M.
3. AT point M(RBSESolutions.com)construct ∠LMN = 105° and cut arc MN = 3.8 cm on MY. Mark the point as N.
4. Join KN.
Thus, KLMN is a required quadrilateral.

Question 2.
Construct a quadrilateral ABCD in which AB = BC = 3 cm., AD = 5 cm., ∠A = 90° and ∠B = 105°.
Solution
First of all(RBSESolutions.com)we draw a rough sketch of the given measurements :

Steps of Construction

1. First of all we draw a line segment AB = 3 cm.
2. At point(RBSESolutions.com)A we construct ∠BAX = 90° with AB and cut AD = 5.0 cm.
3. Similarly, we construct at point B, ∠ABY = 105° with AB and an arc of 3 cm. on BY is cut. Mark this point as C.
4. Join CD.
Thus, we obtained the required quadrilateral ABCD.

Question 3.
Construct a quadrilateral PQRS in which QR = 3.6 cm., RS = 4.5 cm., PS = 5.0 cm., ∠R = 75° and ∠S = 120°.
Solution
First of all we draw a rough sketch of given measurements :

Steps of Construction

1. First of all we draw a line segment of line RS = 4.5 cm.
2. At point R we construct ∠SRX = 75° with SR with the help of pencil and compass and
cut an arc 3.6 cm from R on RX mark this point as Q.
3. Similarly, we(RBSESolutions.com)construct an ∠RSY = 120° with RS with the help of pencil and compass from point SR cut an arc of 5 cm. is cut mark this point as P.
4. Join PQ.
Thus, PQRS is a required quadrilateral.

Question 4.
Construct a quadrilateral DEAR in which DE = 4.7 cm., EA = 5.0 cm., AR = 4.5 cm., ∠E = 60° and ∠A = 90°.
Solution
First of all we draw a rough sketch of given measurements :

Steps of Construction

1. Draw a line of segment DE = 4.7 cm.
2. From point E, a ray EX in drawn making an angle of 60° with DE from point E an arc of 5.0 cm is cut on EX and marked the point as A.
3. Similarly, at A, a ray AY is drawn making an angle of 90°. Cut an arc of 4.5 cm on AY and marked the point as R.
4. Join DR.
5. Thus, we obtained(RBSESolutions.com)a required quadrilateral DEAR.

Question 5.
Construct a quadrilateral ABCD in which ∠B = 135°, ∠C = 90°, BC = 5.0 cm., AB = 9.0 cm. and CD = 7.0 cm.
Solution
First of all we draw a rough sketch of given measurements :

Steps of Construction

1. First of all a line segment, AB = 9.0 cm indrawn.
2. Construct ∠ABC = 135° at B with BX cut an arc of 5.0 cm from BX. Mark this points as C.
3. Also at(RBSESolutions.com)point C, make an angle of 90° by a ray CY and cut an arc of 7.0 cm mark this point at D.