Find the mean and median in the absence of the outlier. Class 7

Find the mean and median in the absence of the outlier. Class 7

Question 1.

Find the mean and median in the absence of the outlier. What change do you notice? Class 7

Solution:

Mean = 5[latex]\frac {6}{7}[/latex]. Median = [latex]\frac {5+6}{2}[/latex] = 5.5

Now, they are nearly the same.

Question 2.

Do you read newspapers? Have you noticed how many pages a newspaper has on different days of the week — is it the same or different?

The list below shows the number of pages for a particular newspaper from Monday to Sunday: 16,18,20,22,26,16,10.

Mark the data, the mean, and the median on the dot plot below.

Solution:

Do as directed as shown :

Data:

Mean:

Mean = 18[latex]\frac {2}{7}[/latex]

Median:

Median = 18