Find the sums and diffrences: (a) 3/10 + 3 4/100; (b) 9 5/10 7/100 + 2 1/10 3/100. Class 7

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Maths Class 7 Maths 118 views Jun 04, 2026 Reviewed & updated Sep 17, 2026
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Find the sums and diffrences: (a) 2/10 + 3 4/100; (b) 9 5/10 7/100 + 2 1/10 3/100. Class 7

Question 1.

Find the sums and diffrences: Class 7

(a) [latex]\frac {3}{10}[/latex] + 3[latex]\frac {4}{100}[/latex]

Solution:

= [latex]\frac {30}{100}[/latex] + 3 + [latex]\frac {4}{100}[/latex]

= 3 + [latex]\frac {34}{100}[/latex] = 3[latex]\frac {34}{100}[/latex]

(b) 9[latex]\frac {5}{10}[/latex][latex]\frac {7}{100}[/latex] + 2[latex]\frac {1}{10}[/latex][latex]\frac {3}{100}[/latex]

Solution:

= 9 + [latex]\frac {5}{10}[/latex] + [latex]\frac {7}{100}[/latex] + 2 + [latex]\frac {1}{10}[/latex] + [latex]\frac {3}{100}[/latex]

= 11 + [latex]\frac {6}{10}[/latex] + [latex]\frac {10}{100}[/latex] = 11 + [latex]\frac {60}{100}[/latex] + [latex]\frac {10}{100}[/latex]

= 11 + [latex]\frac {70}{100}[/latex] = 11[latex]\frac {70}{100}[/latex]

(c) 15[latex]\frac {6}{10}[/latex][latex]\frac {4}{100}[/latex] + 14[latex]\frac {3}{10}[/latex][latex]\frac {6}{100}[/latex]

Solution:

15 + [latex]\frac {6}{10}[/latex] + [latex]\frac {4}{100}[/latex] + 14 + [latex]\frac {3}{10}[/latex] + [latex]\frac {6}{100}[/latex]

= 29 + [latex]\frac {9}{10}[/latex] + [latex]\frac {10}{100}[/latex] = 29 + [latex]\frac {90}{100}[/latex] + [latex]\frac {10}{100}[/latex]

= 29 + [latex]\frac {100}{100}[/latex] = 29 + 1 = 30

(d) 7[latex]\frac {7}{100}[/latex] - 4[latex]\frac {4}{100}[/latex]

Solution:

7 + [latex]\frac {7}{100}[/latex] - (4 + [latex]\frac {4}{100}[/latex])

= 3 + [latex]\frac {3}{100}[/latex] = 3[latex]\frac {3}{100}[/latex]

(e) 8[latex]\frac {6}{100}[/latex] - 5[latex]\frac {3}{100}[/latex]

Solution:

= 8 + [latex]\frac {6}{100}[/latex] - (5 + [latex]\frac {3}{100}[/latex])

= 3 + [latex]\frac {3}{100}[/latex] = 3[latex]\frac {3}{100}[/latex]

(f) 12[latex]\frac {6}{10}[/latex][latex]\frac {2}{100}[/latex] - [latex]\frac {9}{10}[/latex][latex]\frac {9}{100}[/latex]

Solution:

= 12 + [latex]\frac {6}{10}[/latex] + [latex]\frac {2}{100}[/latex] - [latex]\frac {9}{10}[/latex] - [latex]\frac {9}{100}[/latex]

= 12 + [latex]\frac {60}{100}[/latex] + [latex]\frac {2}{100}[/latex] - [latex]\frac {90}{100}[/latex] - [latex]\frac {9}{100}[/latex]

= 11 + [latex]\frac {100}{100}[/latex] + [latex]\frac {60}{100}[/latex] + [latex]\frac {2}{100}[/latex] - [latex]\frac {99}{100}[/latex]

= 11 + [latex]\frac {162}{100}[/latex] - [latex]\frac {99}{100}[/latex] = 11 + [latex]\frac {63}{100}[/latex] = 11[latex]\frac {63}{100}[/latex]

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