Find the length of the altitude BY. Class 8

Find the length of the altitude BY. Class 8

Question 1.

Find the length of the altitude BY. Class 8

Solution:

Also, area of ∆ ABC = [latex]\frac{1}{2}[/latex] BC × AX

= [latex]\frac{1}{2}[/latex] × 6 × 4

= 12 sq. units.

Also, area of ∆ ABC = [latex]\frac{1}{2}[/latex] AC × BY

= [latex]\frac{1}{2}[/latex] × 8 × BY sq. units

= 4BY sq. units

So, 4BY =8

or BY = [latex]\frac{8}{4}[/latex] = 2 units.

Question 2.

Find the area of ∆SUB, given that it is isosceles, SE is perpendicular to UB, and the area of ∆SEB is 24 sq. units. Class 8

Solution:

In ∆ SUE and ∆SBE,

SU = SB (Given)

∠SUE = ∠SEB (90°)

SE = SE (Common)

So, ∆ SUE ≅ ∆SBE.

Hence, area of ∆ SUE = area of ∆SBE

So, area of ∆SUB = 2 area of ∆SEB

= 2 × 24 sq. units = 48 sq. units