Now, take four other consecutive numbers. Place' the '+' and ‘-’ signs as you have done before. Find out the results Class 8

Now, take four other consecutive numbers. Place' the '+' and ‘-’ signs as you have done before. Find out the results Class 8

Question 1.

Now, take four other consecutive numbers. Place' the '+' and ‘-’ signs as you have done before. Find out the results of each expression. What do you observe? Class 8

Solution:

5 + 6 + 7 + 8 = 26

5 + 6 + 7 — 8 = 10

5 + 6 — 7 + 8 = 12

5 + 6 — 7 — 8 = —4

5 — 6 + 7 + 8 = 14

5 — 6 + 7 — 8 = —2

5 — 6 — 7 + 8 = 0

5 — 6 — 7 — 8 = —16

The sum is divisible by 2.

Question 4.

Repeat this for one more set of 4 consecutive numbers. Share your findings. Class 8

Some sums appear always no matter which 4 consecutive numbers are chosen. Isn’t that interesting?

Solution:

Do as directed. Sum in each case will come out to be divisible by 2, i.e., an even integer.