Find three consecutive numbers such that the first number is a multiple of 2, the second number Class 8

Find three consecutive numbers such that the first number is a multiple of 2, the second number Class 8

Question 1.

Find three consecutive numbers such that the first number is a multiple of 2, the second number is a multiple of 3, and the third number is a multiple of 4. Class 8

Are there more such numbers? How often do they occur?

Solution:

One triplet of such numbers is 14, 15, 16.

Other triplets are 26, 27, 28 or 38, 39, 40.

They are occurring at an interval of 12 numbers. For example, 26 - 14 = 12, 38 - 26 = 12, 50 - 38 = 12, 62 - 50 = 12 etc.

Question 2.

Write five multiples of 36 between 45,000 and 47,000. Share your approach with the class. Class 8

Solution:

Multiples are 45036, 45072, 45108, 46044,46116.

Do as directed. Approach is that the number must be divisible by 9 and 4. For 9, sum of the digits be kept as a multiple of 9 and last two digits of the number should form a number divisible by 4.