Due to heavy rains, Snehal could not transport strawberries to Hyderabad from his farm in Panchgani. Class 8

Due to heavy rains, Snehal could not transport strawberries to Hyderabad from his farm in Panchgani. Class 8

Question 1.

Due to heavy rains, Snehal could not transport strawberries to Hyderabad from his farm in Panchgani. Class 8

He sells some of his stock at ₹ 80 per kg with a 12% loss.

What is the cost price?

Solution:

Let C.P. be ₹ x per kg.

Loss = [latex]\frac{12}{100}[/latex] of ₹ x = ₹[latex]\frac{12 x}{100}[/latex] per kg.

So, S.P. per kg = [latex]\left(x-\frac{12 x}{100}\right)[/latex] = ₹ [latex]\frac{88 x}{100}[/latex]

Hence, [latex]\frac{88 x}{100}[/latex] = 80.

So,x = [latex]\frac{80}{88}[/latex] x 100 = [latex]\frac{1000}{11}[/latex] = ?90[latex]\frac{10}{11}[/latex]

Question 2.

A utensil store is offering a 35% discount on the cooker with an MRP ₹ 1800. What is the selling price? If the cost price was ₹ 900, what is the percentage profit made after the sale? Class 8

Solution:

Discount of MRP = 35% of ₹ 1800

= [latex]\frac{35}{100}[/latex] × ₹1800

= ₹ 630.

So, S.P. = ₹ 1800 - ₹ 630

= ₹ 1170

C.P. = ₹ 900

So, profit = ₹1170 - ₹ 900

= ₹ 270

Hence, profit % = [latex]\frac{270}{900}[/latex] × 100 = 30%.