Quadrilaterals Class 8 Short Question Answer

Quadrilaterals Class 8 Short Question Answer

Quadrilaterals Class 8 Short Question Answer

Question 1.

Find the values of x, y and z in the following parallelogram.

Solution:

x = 100° (opposite angles of a parallelogram are equal)

y + 100° = 180°

So, y = 180° - 100° = 80°.

Further z = y = 80°.

Question 2.

Find the values of x and y in the following rhombus PQRS.

Solution:

From ∆OPQ, 90° + x + 30° = 180°.

So, x = 180° - 90° - 30° = 60°.

As diagonals of a rhombus bisect each other, therefore

∠PQR = 2 x 30° = 60°

So, ∠PSR = y = ∠PQR = 60°.

Question 3.

Find the values of x and y in the following parallelogram ABCD.

Solution:

3x + 2x = 180° (Adjacent angles of a ||gm)

or 5x = 180°

or x = [latex]\frac{180^{\circ}}{5}[/latex] = 36°.

y = 2x = 2 × 36° = 72°.

Question 4.

Find the values of x, y and z in the parallelogram PQRS.

Solution:

x = 50° (Opposite angles of a ||gm)

x + y = 180°

So, y = 180° - 50° = 130°.

Now, ∠1 =y = 130°

So, z = 180° - 130° = 50°.

Question 5.

Find the values of x, y and z in the parallelogram DEFG.

Solution:

x = 110° (Opposite angles of a ||gm)

Now, x + y + 40° = 180°

So, 110° + 40°+ y = 180°

y = 180°- 110°- 40° = 30°

So, ∠z = ∠y - 30° (Alternate angles)