Find the area of a rectangle of sides 3 3/4ft and 9 3/5 ft. Class 7

Find the area of a rectangle of sides 3 3/4ft and 9 3/5 ft. Class 7

Question 1.

Find the area of a rectangle of sides 3[latex]\frac {3}{4}[/latex]ft and 9[latex]\frac {3}{5}[/latex] ft. Class 7

Solution:

Area of the rectangle

= Length × Breadth

= 3[latex]\frac {3}{4}[/latex] × 9[latex]\frac {3}{5}[/latex]sq. feet

= [latex]\frac {15}{4}[/latex] × [latex]\frac {48}{5}[/latex]sq. feet

= [latex]\frac{3 \times 12}{1 \times 1}[/latex] = 36 sq. feet

Question 2.

Tsewang plants four saplings in a row in his garden. The distance between two saplings is [latex]\frac {3}{4}[/latex]m. Find the distance between the first and last sapling. [Hint: Draw a rough diagram with four saplings with distance between two saplings as [latex]\frac {3}{4}[/latex]m.] Class 7

Solution:

Distance between first and the last sapling

= 3 × [latex]\frac {3}{4}[/latex]m = [latex]\frac {3}{1}[/latex] × [latex]\frac {3}{4}[/latex]m

= [latex]\frac{3 \times 3}{1 \times 4}[/latex]m = [latex]\frac {9}{4}[/latex]m = 2[latex]\frac {1}{4}[/latex]m

Question 3.

Which is heavier: [latex]\frac {12}{15}[/latex] of 500 grams or [latex]\frac {3}{20}[/latex] of 4 kg? Class 7

Solution:

[latex]\frac {12}{15}[/latex] of 500 grams = [latex]\frac {12}{15}[/latex] × 500 grams

= [latex]\frac {4}{5}[/latex] × 500 grams

= 4 × 100 grams

= 400 grams

[latex]\frac {3}{20}[/latex] of 4 kg = [latex]\frac {3}{20}[/latex] × 4

= [latex]\frac {3}{20}[/latex] × 4000

= 3 × 200 grams

= 600 grams

Also, 600 grams > 400 grams, so [latex]\frac {3}{20}[/latex] of 4 kg is heavier.